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📜  如果某人在某些天后离开,则完成任务所需的总天数

📅  最后修改于: 2021-06-01 01:31:58             🧑  作者: Mango

假设人A几天的时间做某件工作,而人B花了b天的时间做同样的工作。如果AB一起开始工作,并且在工作完成前n天,则A离开工作。查找完成工作所需的总天数。

例子:

方法:D为完成工作的总天数。 AB一起工作了D – n天。所以,

下面是上述方法的实现:

C++
// C++ implementation of the approach
#include 
using namespace std;
 
// Function to return the
// number of days required
int numberOfDays(int a, int b, int n)
{
    int Days = b * (n + a) / (a + b);
 
    return Days;
}
 
// Driver code
int main()
{
    int a = 10, b = 20, n = 5;
 
    cout << numberOfDays(a, b, n);
 
    return 0;
}


Java
// Java implementation of the approach
import java.io.*;
 
class GFG
{
     
// Function to return the
// number of days required
static int numberOfDays(int a, int b, int n)
{
    int Days = b * (n + a) / (a + b);
 
    return Days;
}
 
// Driver code
public static void main (String[] args)
{
 
    int a = 10, b = 20, n = 5;
    System.out.println (numberOfDays(a, b, n));
 
}
}
 
// This code is contributed by jit_t


Python3
# Python3 implementation of the approach
  
# Function to return the
# number of days required
def numberOfDays(a, b, n):
 
    Days = b * (n + a) // (a + b)
  
    return Days
 
# Driver code
if __name__ == "__main__" :
 
    a = 10
    b = 20
    n = 5
  
    print(numberOfDays(a, b, n))
 
# This code is contributed by rrrtnx


C#
// C# implementation of the approach
using System;
 
class GFG
{
     
    // Function to return the
    // number of days required
    static int numberOfDays(int a, int b, int n)
    {
        int Days = b * (n + a) / (a + b);
     
        return Days;
    }
     
    // Driver code
    public static void Main ()
    {
     
        int a = 10, b = 20, n = 5;
        Console.WriteLine(numberOfDays(a, b, n));
     
    }
}
 
// This code is contributed by AnkitRai01


Javascript


输出:
10

时间复杂度: O(1)

辅助空间: O(1)