📜  C++ STL中的bitset all()函数

📅  最后修改于: 2021-05-30 09:02:12             🧑  作者: Mango

bitset :: all()是C++ STL中的内置函数,如果所有位都以数字的二进制表示形式设置(如果在位集中进行了初始化),则该函数将返回True。如果未设置所有位,则返回False。

句法:

bool bitset_name.all() 

参数:此函数不接受任何参数。

返回值:该函数返回一个布尔值。如果所有位均已设置,则返回的布尔值是true,否则返回false,

下面的程序说明了bitset :: all()函数。

程序1:

// CPP program to illustrate the
// bitset::all() function
#include 
using namespace std;
  
int main()
{
    // Initialization of bitset
    bitset<4> b1(string("1100"));
    bitset<6> b2(string("111111"));
  
    // Function that checks if all
    // the bits are set or not
    bool result1 = b1.all();
    if (result1)
        cout << b1 << " has all bits set"
             << endl;
    else
        cout << b1 << " does not have all bits set"
             << endl;
  
    // Function that checks if all
    // the bits are set or not
    bool result2 = b2.all();
    if (result2)
        cout << b2 << " has all bits set"
             << endl;
    else
        cout << b2 << " does not have all bits set"
             << endl;
  
    return 0;
}
输出:
1100 does not have all bits set
111111 has all bits set

程式2:

// CPP program to illustrate the
// bitset::all() function
// when the input is as a number
  
#include 
using namespace std;
  
int main()
{
    // Initialization of bitset
    bitset<2> b1(3);
    bitset<3> b2(5);
  
    // Function that checks if all
    // the bits are set or not
    bool result1 = b1.all();
    if (result1)
        cout << b1 << " has all bits set"
             << endl;
    else
        cout << b1 << " does not have all bits set"
             << endl;
  
    // Function that checks if all
    // the bits are set or not
    bool result2 = b2.all();
    if (result2)
        cout << b2 << " has all bits set"
             << endl;
    else
        cout << b2 << " does not have all bits set"
             << endl;
  
    return 0;
}
输出:
11 has all bits set
101 does not have all bits set
要从最佳影片策划和实践问题去学习,检查了C++基础课程为基础,以先进的C++和C++ STL课程基础加上STL。要完成从学习语言到DS Algo等的更多准备工作,请参阅“完整面试准备课程”