C＃中的Double.IsNegativeInfinity()方法

在C＃中， Double.IsNegativeInfinity()是Double结构方法。此方法用于检查指定的值是否等于负无穷大。在某些浮点运算中，有可能获得负无穷大的结果。例如：如果任何负值除以零，则结果为负无穷大。

Syntax: public static bool IsNegativeInfinity (double d);
Parameter:
d: It is a double-precision floating-point number of type System.Double.

返回类型：如果指定值的计算结果为负无穷大，则此函数返回布尔值True ，否则返回False 。

例子：

Input  : d = -5.0 / 0.0 
Output : True

Input  : d = -1.5935e250 * 7.948e110
Output : True

代码：演示Double.IsNegativeInfinity(Double)方法

// C# program to illustrate the
// Double.IsNegativeInfinity() Method
using System;
  
class GFG {
  
    // Main method
    static public void Main()
    {
  
        // Dividing a negtaive number by zero
        // results in Negative infinity.
  
        // Dividing a number directly by 0
        // produces an error
        // So 0 is stored in a variable first
  
        double zero = 0.0;
        double value = -5;
        double result = value / zero;
  
        // Printing result
        Console.WriteLine(result);
  
        // Check result using IsNegativeInfinity() Method
        Console.WriteLine(Double.IsNegativeInfinity(result));
  
        // Result of floating point operation
        // that is less than Double.MinValue
        // is Negative Infinity
  
        result = Double.MinValue * 7.948e110;
  
        // Printing result
        Console.WriteLine(result);
  
        // Check result using IsNegativeInfinity() Method
        Console.WriteLine(Double.IsNegativeInfinity(result));
    }
}

输出：

-Infinity
True
-Infinity
True

笔记：

• 小于Double.MinValue(即-1.7976931348623157E + 308)的任何浮点运算的结果都被视为负无穷大。
• 浮点运算返回Infinity (正无穷大)或-Infinity (负无穷大)以指示溢出情况。