TCS安置纸| MCQ 7

这是用于能力倾向准备的TCS模型放置论文。这份安置文件将涵盖在TCS招聘活动中提出的才能问题，并且还将严格遵循在TCS面试中提出的问题模式。建议解决以下每个问题，以增加清除TCS面试的机会。

1. 相同长度的木棒用于形成三角形，如下所示。如果使用87个这样的棒，那么可以形成多少个三角形?
   
   a)42
   b)43
   c)44
   d)45

   Answer: b) 43

   Solution:
   As we can see the first triangle can be formed using 3 sticks. So we have 87 – 3 = 84 sticks left.
   So every next triangle can be formed using 2 sticks.
   So we have 84/2 = 42 triangles and 43 triangles in all.

2. 在3、12、7、26、15 、?系列中找到下一个数字
   a)54
   b)55
   c)64
   d)74

   Answer: a) 54

   Solution:
   3 * 2 + 1 = 7
   12 * 2 + 2 = 26
   7 * 2 + 1 = 15
   26 * 2 + 2 = 54

3. 有一个玩具枪可以发出10个音乐声。不良后发出2种音乐声。同一音乐声音连续产生5次的概率是多少?
   a)1/16
   b)1/32
   c)1/48
   d)1/2

   Answer: b) 1/32

   Solution:
   The probability of making the same sound every time = 1/2,
   So, 1/2^5 = 1/32 (answer)

4. 您可以用多少种可能的方式将3240写成3个正整数的乘积?
   a)320
   b)420
   c)350
   d)450

   Answer: d) 450 ways

   Solution:
   First let’s prime factorize the number 3240 = $$2^3 * 3^4 * 5^1$$
   Let the three positive numbers be x, y and z
   We have to distribute three 2’s to x, y and z ways in (3+3-1)C(3-1) = 5C2 ways = 10 ways
   We have to distribute four 3’s to x, y, z in (3+4-1)C(3-1) = 6C2 ways
   We have to distribute one 5 to x, y, z in 3 ways.
   The total number of ways = 10×15×3=450 ways.

5. 衬衫的标价比建议零售价低40％。 Ram在15周年的拍卖会上以标价的一半购买了这件大衣。 Ram支付的建议零售价低百分之几?
   a)70％
   b)20％
   c)60％
   d)30％

   Answer: a) 70%

   Solution:
   Let the retail price of the shirt be Rs. 100
   So according to the question, the market price will be = 100*0.6 = 60
   Purchased price of Ram = 60/2 = 30
   which is 70% less than retail price.

6. HCF 2472、1284和第三个数字是12。如果它们的LCM是8 * 9 * 5 * 103 * 107，那么数字是多少?
   a)2 ^ 2 * 3 ^ 2 * 7 ^ 1
   b)2 ^ 2 * 3 ^ 2 * 5 ^ 1
   c)2 ^ 2 * 3 ^ 2 * 8103
   d)以上都不是。

   Answer: b) 2^2×3^2×5^1

   Solution:
   2472 = $$2^3*3*103$$
   1284 = $$2^2*3*107$$
   HCF = $$2^2*3$$
   LCM = $$2^3*3^2*5*103*107$$
   HCF of the number is the highest number which divides all the numbers. So N should be a multiple of 22×3
   LCM is the largest number that is divided by the given numbers. As LCM contains 32×5 these two are from N.
   So N = [Tex]$2^2×3^2×5^1$[Tex]

7. 从公寓步行到办公室，一位老人需要30分钟，而一位年轻人则需要20分钟。如果有一天，老人从公寓到办公室开始于上午10:00，年轻人在上午10:05开始，他们何时会见?
   a)10:00
   b)10:15
   c)10.30
   d)10:45

   Answer: b) 10:15

   Solution:
   Let the distance of the apartment from the office be 12 km
   So the speed of the old man = 12 / (1/2) hr = 24 km/hr
   The young man speed = 12 / (1/3) hr = 36 km/hr
   Since the old man started 5 minutes earlier, he covers 24 × (5/60) = 2 km in 5 minutes.
   Now the time taken to the young man to meets him = 2/(36-24) * 60 = 10 minutes
   So the time of meet = 10:05 + 10 = 10 hr 15 min or 10:15

8. 在112到375的范围内，有多少个2?
   a)312
   b)156
   c)159
   d)160

   Answer: b) 156

   Solution:
   The total number of 2’s in the units place = (122, 132, 142 … 192), (201, 212, 222, … 292), (302, 312, … 372) = 8 + 10 + 8 = 26 2’s
   The total number of 2’s in tenth’s place = (120, 121, 122, …, 129) + (220, 221, …, 229) + (320, 321, …, 329) = 30
   The total number of 2’s in hundred’s place = (200, 201, … 299) = 100.
   So the total number of 2’s between 112 and 375 = 26 + 30 + 100 = 156

9. Ram行走36公里，部分速度为4 km / hr，部分速度为3 km / hr。如果他以3 km / hr的速度行走，而以3 km / hr的速度行走，则以3 km / hr的速度行走，那么他只能行走34 km。拉姆走路所花费的时间(以小时为单位)为
   a)10
   b)5
   c)12
   d)8

   Answer: a) 10

   Solution:
   Let Ram walk ‘x’ hrs at 4 km/hr, and ‘y’ hrs at 3 km/hr.
   Given,
   4x + 3y = 36
   3x + 4y = 34
   Solving these two equations we get x + y = 10

10. PERFECT单词的字母排列中的第55个单词是什么?
    a)CEPFRET
    b)CEPFERT
    c)CEPERFT
    d)CEPRFET

    Answer: b) CEPFERT

    Solution:
    Let’s arrange the word PERFECT in dictionary order = CEEFPRT
    Here,
    CEE(4!)=24
    CEF(4!)=24
    CEPF(3!)=6
    So the 55th word is CEPFERT.