Java中的 AbstractSequentialList retainAll() 方法与示例

Java.util.AbstractSequentialList类的retainAll()方法用于从此列表中保留指定集合中包含的所有元素。

句法：

public boolean retainAll(Collection c)

参数：此方法将集合 c作为参数，其中包含要从此列表中保留的元素。

返回值：如果此列表因调用而更改，则此方法返回true 。

异常：如果此列表包含空元素并且指定的集合不允许空元素（可选），或者指定的集合为空，则此方法将引发NullPointerException 。

下面是说明retainAll()方法的示例。

示例 1：

// Java program to demonstrate
// retainAll() method for Integer value
  
import java.util.*;
  
public class GFG1 {
    public static void main(String[] argv) throws Exception
    {
  
        try {
  
            // Creating object of AbstractSequentialList
            AbstractSequentialList
                arrlist1 = new LinkedList();
  
            // Populating arrlist1
            arrlist1.add(1);
            arrlist1.add(2);
            arrlist1.add(3);
            arrlist1.add(4);
            arrlist1.add(5);
  
            // print arrlist1
            System.out.println("AbstractSequentialList before "
                               + "retainAll() operation : "
                               + arrlist1);
  
            // Creating another object of  AbstractSequentialList
            AbstractSequentialList
                arrlist2 = new LinkedList();
            arrlist2.add(1);
            arrlist2.add(2);
            arrlist2.add(3);
  
            // print arrlist2
            System.out.println("Collection Elements"
                               + " to be retaind : "
                               + arrlist2);
  
            // Removing elements from arrlist
            // specified in arrlist2
            // using retainAll() method
            arrlist1.retainAll(arrlist2);
  
            // print arrlist1
            System.out.println("AbstractSequentialList after "
                               + "retainAll() operation : "
                               + arrlist1);
        }
  
        catch (NullPointerException e) {
            System.out.println("Exception thrown : " + e);
        }
    }
}

输出：

AbstractSequentialList before retainAll() operation : [1, 2, 3, 4, 5]
Collection Elements to be retaind : [1, 2, 3]
AbstractSequentialList after retainAll() operation : [1, 2, 3]

示例 2：对于NullPointerException

// Java program to demonstrate
// retainAll() method for Integer value
  
import java.util.*;
  
public class GFG1 {
    public static void main(String[] argv) throws Exception
    {
  
        try {
  
            // Creating object of AbstractSequentialList
            AbstractSequentialList
                arrlist1 = new LinkedList();
  
            // Populating arrlist1
            arrlist1.add(1);
            arrlist1.add(2);
            arrlist1.add(3);
            arrlist1.add(4);
            arrlist1.add(5);
  
            // print arrlist1
            System.out.println("AbstractSequentialList before "
                               + "retainAll() operation : "
                               + arrlist1);
  
            // Creating another object of  AbstractSequentialList
            AbstractSequentialList
                arrlist2 = null;
  
            // print arrlist2
            System.out.println("Collection Elements"
                               + " to be retaind : "
                               + arrlist2);
  
            System.out.println("\nTrying to pass "
                               + "null as a specified element\n");
  
            // Removing elements from arrlist
            // specified in arrlist2
            // using retainAll() method
            arrlist1.retainAll(arrlist2);
  
            // print arrlist1
            System.out.println("AbstractSequentialList after "
                               + "retainAll() operation : "
                               + arrlist1);
        }
  
        catch (NullPointerException e) {
            System.out.println("Exception thrown : " + e);
        }
    }
}

输出：

AbstractSequentialList before retainAll() operation : [1, 2, 3, 4, 5]
Collection Elements to be retaind : null

Trying to pass null as a specified element

Exception thrown : java.lang.NullPointerException