Java中的 AbstractSequentialList remove() 方法及示例

AbstractSequentialList的remove(int index)方法用于从特定位置或索引的抽象顺序列表中删除元素。

句法：

AbstractSequentialList.remove(int index)

参数：参数索引是整数数据类型，并指定要从 AbstractSequentialList 中删除的元素的位置。

返回值：此方法返回刚刚从列表中删除的元素。

下面的程序说明了 AbstractSequentialList.remove(int index) 方法：

方案一：

// Java code to illustrate remove() method
  
import java.util.*;
import java.util.AbstractSequentialList;
  
public class AbstractSequentialListDemo {
    public static void main(String args[])
    {
  
        // Creating an empty AbstractSequentialList
        AbstractSequentialList
            absqlist = new LinkedList();
  
        // Using add() method to add elements in the list
        absqlist.add("Geeks");
        absqlist.add("for");
        absqlist.add("Geeks");
        absqlist.add("10");
        absqlist.add("20");
  
        // Output the list
        System.out.println("AbstractSequentialList: "
                           + absqlist);
  
        // Remove the head using remove()
        absqlist.remove(3);
  
        // Print the final list
        System.out.println("Final List: "
                           + absqlist);
    }
}

输出：

AbstractSequentialList: [Geeks, for, Geeks, 10, 20]
Final List: [Geeks, for, Geeks, 20]

方案二：

// Java code to illustrate remove()
// with position of element passed as parameter
  
import java.util.*;
import java.util.AbstractSequentialList;
  
public class AbstractSequentialListDemo {
    public static void main(String args[])
    {
  
        // Creating an empty AbstractSequentialList
        AbstractSequentialList
            absqlist = new LinkedList();
  
        // Use add() method to add elements in the list
        absqlist.add("Geeks");
        absqlist.add("for");
        absqlist.add("Geeks");
        absqlist.add("10");
        absqlist.add("20");
  
        // Output the list
        System.out.println("AbstractSequentialList:"
                           + absqlist);
  
        // Remove the head using remove()
        absqlist.remove(0);
  
        // Print the final list
        System.out.println("Final AbstractSequentialList:"
                           + absqlist);
    }
}

输出：

AbstractSequentialList:[Geeks, for, Geeks, 10, 20]
Final AbstractSequentialList:[for, Geeks, 10, 20]