8类RD Sharma解决方案–第7章分解–练习7.2

分解以下内容：

问题1. 3x – 9

解决方案：

The highest common factor in the above two terms – 3

3x – 9

3(x – 3)

问题2。5x– 15x ²

解决方案：

The highest common factor in the above two terms – 5x

5x – 15x²

5x (1 – 3x)

问题3。20a ¹² b ² – 15a ⁸ b ⁴

解决方案：

The highest common factor in the above two terms – 5a⁸b²

20a¹²b² – 15a⁸b⁴

5a⁸b² (4a⁴ – 3b²)

问题4. 72x ^6年7 – 96x ^7年6

解决方案：

The highest common factor in the above two terms -24x⁶y⁶

72x⁶y⁷ – 96x⁷y⁶

24x⁶y⁶ (3y – 4x)

问题5：20x ³ – 40x ² + 80x

解决方案：

The highest common factor in the above three terms – 20x

20x³ – 40x² + 80x

20x (x² – 2x +4)

问题6. 2x ^3年2 – 4x ^2年3 + 8年⁴

解决方案：

The highest common factor in the above three terms – 2xy²

2x³y² – 4x²y³ + 8xy⁴

2xy² (x² – 2xy + 4y²)

问题7. 10m ³ n ² + 15m ⁴ n – 20m ² n ³

解决方案：

The highest common factor in the above three terms – 5mn2

10m³n² + 15m⁴n – 20m²n³

5m²n (2mn + 3m² – 4n²)

问题8. 2a ⁴ b ⁴ – 3a ³ b ⁵ + 4a ² b ⁵

解决方案：

The highest common factor in the above three terms – a²b⁴

2a⁴b⁴ – 3a³b⁵ + 4a²b⁵

a²b⁴ (2a² – 3ab + 4b)

问题9. 28a ² + 14a ² b ² – 21a ⁴

解决方案：

The highest common factor in the above three terms – 7a²

28a² + 14a²b² – 21a⁴

7a² (4a + 2b² – 3a²)

问题10. a ⁴ b – 3a ² b ² – 6ab ³

解决方案：

The highest common factor in the above three terms – ab

a⁴b – 3a²b² – 6ab³

ab (a³ – 3ab – 6b²)

问题11. 2l ² mn – 3lm ² n + 4lmn ²

解决方案：

The highest common factor in the above three terms – lmn

2l²mn – 3lm²n + 4lmn²

lmn (2l – 3m + 4n)

问题12. x ⁴ y ² – x ² y ⁴ – x ⁴ y ⁴

解决方案：

The highest common factor in the above three terms – x2y2

x⁴y² – x²y⁴ – x⁴y⁴

x²y²(x² – y² – x²y²)

问题^{13.9x 2年}+ 3年

解决方案：

The highest common factor in the above two terms – 3xy

9x²y + 3axy

3xy(3x + a)

问题14. 16m – 4m ²

解决方案：

The highest common factor in the above two terms – 4m

16m – 4m²

4m(4 – m)

问题15 -4a ² + 4ab – 4ca

解决方案：

The highest common factor in the above three terms – (–4a)

-4a² + 4ab – 4ca

-4a(a – b + c)

问题16. x ² yz + xy ² z + xyz ²

解决方案：

The highest common factor in the above three terms – xyz

x²yz + xy²z + xyz²

xyz(x + y + z)

问题17斧² Y + BXY ² + cxyz

解决方案：

The highest common factor in the above three terms – xy

ax²y + bxy² + cxyz

xy(ax + by + cz)