字符串中的泛字母窗口

给定一个大小为n的字符串S。任务是检查给定的字符串是否包含泛字母窗口。 Panalphabetic 窗口是一段文本，其中包含按顺序排列的所有字母。
例子：

Input : S = "abujm zvcd acefc deghf gijkle m n o p pafqrstuvwxyzfap"
Output : YES
Panalphabetic Window is in Bold:
abujm zvcd acefc deghf gijkle m n o p pafqrstuvwxyzfap

Input : S = "geeksforgeeks"
Output : NO

这个想法是初始化一个变量，比如ch，为'a'。从头开始遍历给定的字符串，如果我们找到一个等于 ch 的字符，则将变量 ch 加 1，否则移动到下一个索引。当字符串结束时检查 ch 是否等于 'z' + 1，如果是，则返回 true，否则返回 false。
下面是这种方法的实现：

C++

// CPP Program to check whether given string contain
// panalphabetic window or not
#include
using namespace std;
 
// Return if given string contain panalphabetic window.
bool isPanalphabeticWindow(char s[], int n)
{
    char ch = 'a';
     
    // traversing the string
    for (int i = 0; i < n; i++)
    {
        // if character of string is equal to ch, 
        // increment ch.
        if (s[i] == ch)
            ch++;
             
        // if all characters are found, return true.
        if (ch == 'z' + 1)
            return true;
    }
     
    return false;
}
// Driven Program
int main()
{
    char s[] = "abujm zvcd acefc deghf gijkle"
                " m n o p pafqrstuvwxyzfap";
    int n = strlen(s);
     
    (isPanalphabeticWindow(s, n))?(cout << "YES"):
                                  (cout << "NO");
 
    return 0;
}

Java

// Java Program to check whether given
// string contain panalphabetic
// window or not
class GFG
{
     
    // Return if given string contain
    // panalphabetic window.
    static boolean isPanalphabeticWindow(String s, 
                                            int n)
    {
        char ch = 'a';
         
        // traversing the string
        for (int i = 0; i < n; i++)
        {
            // if character of string is equal 
            // to ch, increment ch.
            if (s.charAt(i) == ch)
                ch++;
                 
            // if all characters are
            // found, return true.
            if (ch == 'z' + 1)
                return true;
        }
         
        return false;
}
 
// Driver code
public static void main (String[] args)
{
    String s = "abujm zvcd acefc deghf"
       + " gijklem n o p pafqrstuvwxyzfap";
    int n = s.length();
     
    if(isPanalphabeticWindow(s, n))
            System.out.print("YES");
    else
        System.out.print("NO");
}
}
 
// This code is contributed by
// Anant Agarwal.

Python3

# Python Program to check
# whether given string
# contain panalphabetic
# window or not
 
# Return if given string
# contain panalphabetic window.
def isPanalphabeticWindow(s, n) :
 
    ch = 'a'
     
    # traversing the string
    for i in range(0, n) :
     
        # if character of string
        # is equal to ch, increment ch.
        if (s[i] == ch) :
            ch = chr(ord(ch) + 1)
             
        # if all characters are
        # found, return true.
        if (ch == 'z') :
            return True
             
    return False
 
# Driver Code
s = "abujm zvcd acefc deghf gijkle m n o p pafqrstuvwxyzfap"
n = len(s)
 
if(isPanalphabeticWindow(s, n)) :
    print ("YES")
else :
    print ("NO")
     
# This code is contributed by
# Manish Shaw(manishshaw1)

C#

// C# Program to check whether given
// string contain panalphabetic
// window or not
using System;
 
class GFG
{
     
    // Return if given string contain
    // panalphabetic window.
    static bool isPanalphabeticWindow(string s,
                                            int n)
    {
        char ch = 'a';
         
        // traversing the string
        for (int i = 0; i < n; i++)
        {
            // if character of string is equal
            // to ch, increment ch.
            if (s[i] == ch)
                ch++;
                 
            // if all characters are
            // found, return true.
            if (ch == 'z' + 1)
                return true;
        }
         
        return false;
}
 
    // Driver code
    public static void Main ()
    {
        string s = "abujm zvcd acefc deghf"
        + " gijklem n o p pafqrstuvwxyzfap";
        int n = s.Length;
         
        if(isPanalphabeticWindow(s, n))
                Console.WriteLine("YES");
        else
            Console.WriteLine("NO");
    }
}
 
// This code is contributed by
// Vt_m.

Javascript

 
// Javascript Program to check whether given string contain
// panalphabetic window or not
 
// Return if given string contain panalphabetic window.
function isPanalphabeticWindow(s, n)
{
    var ch = 'a';
     
    // traversing the string
    for (var i = 0; i < n; i++)
    {
        // if character of string is equal to ch, 
        // increment ch.
        if (s[i] == ch)
            ch = String.fromCharCode(ch.charCodeAt(0) + 1);
             
        // if all characters are found, return true.
        if (ch == String.fromCharCode('z'.charCodeAt(0) + 1))
            return true;
    }
     
    return false;
}
 
// Driven Program
var s = "abujm zvcd acefc deghf"
        + " gijklem n o p pafqrstuvwxyzfap";
var n = (s.length);
 
(isPanalphabeticWindow(s, n))?(document.write( "YES")):
                              (document.write( "NO"));
 
// This code is contributed by itsok.

输出：

YES

https://youtu.be/HQY36

-伊玛格