画一个没有浮点数的圆

给定圆的半径，请在不使用浮点算法的情况下绘制圆。
以下程序使用一个简单的概念。令圆的半径为r。考虑要绘制的圆周围大小为(2r + 1)*(2r + 1)的正方形。现在，走过广场内的每个点。对于每个点(x，y)，如果(x，y)位于圆内(或x ^ 2 + y ^ 2

C++

// C++ program to draw a circle without
// floating point arithmetic
#include 
 
void drawCircle(int r)
{
    // Consider a rectangle of size N*N
    int N = 2*r+1;
 
    int x, y;  // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i-r;
            y = j-r;
 
            // If this point is inside the circle, print it
            if (x*x + y*y <= r*r+1 )
                printf(".");
            else // If outside the circle, print space
                printf(" ");
            printf(" ");
        }
        printf("\n");
    }
}
 
// Driver Program to test above function
int  main()
{
    drawCircle(8);
    return 0;
}

Java

// Java program to draw a circle without
// floating point arithmetic
 
import java.io.*;
 
class GFG {
static void drawCircle(int r)
{
    // Consider a rectangle of size N*N
    int N = (2*r+1);
 
    int x, y; // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i-r;
            y = j-r;
 
            // If this point is inside the circle, print it
            if (x*x + y*y <= r*r+1 )
                    System.out.print(".");
            else // If outside the circle, print space
                    System.out.print(" ");
                System.out.print(" ");
        }
            System.out.println();
    }
}
 
// Driver Program to test above function
    public static void main (String[] args) {
        drawCircle(8);
    }
//This code is contributed by ajit.
}

Python3

# Python3 program to draw a circle without
# floating point arithmetic
def drawCircle(r) :
     
    # Consider a rectangle of size N*N 
    N = 2*r + 1
   
    # Draw a square of size N*N. 
    for i in range(N) :    
        for j in range(N) :
         
            # Start from the left most corner point 
            x = i - r 
            y = j - r
   
            # If this point is inside the circle, print it 
            if (x * x + y * y <= r * r + 1 ) :
                print(".", end = "")
            else :# If outside the circle, print space 
                print(" ", end = "") 
            print(" ", end = "")
             
        print()
             
drawCircle(8)
 
# This code is contributed by divyeshrabadiya07.

C#

// C#  program to draw a circle without
// floating point arithmetic
 
using System;
 
public class GFG{
    static void drawCircle(int r)
{
    // Consider a rectangle of size N*N
    int N = (2*r+1);
 
    int x, y; // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i-r;
            y = j-r;
 
            // If this point is inside the circle, print it
            if (x*x + y*y <= r*r+1 )
                    Console.Write(".");
            else // If outside the circle, print space
                    Console.Write(" ");
                Console.Write(" ");
        }
            Console.WriteLine();
    }
}
 
// Driver Program to test above function
    static public void Main (){
        drawCircle(8);
    }
//This code is contributed by Sachin.
}

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