程序使用电路中给定的颜色代码计算电阻

有许多不同类型的电阻器可用于电路和电子电路。电阻值，容差和瓦特额定值通常以色带的形式印在电阻器的主体上。任务是找到4频段电阻器和5频段电阻器的电阻。

查找4频段电阻器电阻的程序

给定四个字符串A ， B ， C和D ，它们表示4波段电阻器的颜色代码。任务是使用给定的颜色代码查找电阻，公差和瓦特数额定值。

例子：

Input: A = “black”, B = “brown”, C = “red”, D = “green”
Output: Resistance = 01 x 100 ohms +/- 0.5 %

Input: A = “red”, B = “orange”, C = “yellow”, D = “green”
Output: Resistance = 23 x 10k ohms +/- 0.5 %

方法：想法是将数字和乘法器存储在哈希图中，然后可以计算电阻器的电阻。

下面是上述方法的实现：

Python3

# Python implementation to find the 
# resistance of the resistor with
# the given color codes
  
# Function to find the resistance 
# using color codes
def findResistance(a, b, c, d):
      
    # Hash-map to store the values 
    # of the color-digits
    color_digit = {'black': '0',
                   'brown': '1', 
                   'red': '2',
                   'orange': '3', 
                   'yellow': '4',
                   'green' : '5', 
                   'blue' : '6',
                   'violet' : '7', 
                   'grey' : '8',
                   'white': '9'}
      
    multiplier = {'black': '1',
                  'brown': '10', 
                  'red': '100', 
                  'orange': '1k', 
                  'yellow': '10k', 
                  'green' : '100k', 
                  'blue' : '1M', 
                  'violet' : '10M', 
                  'grey' : '100M', 
                  'white': '1G'}
      
    tolerance = {'brown': '+/- 1 %', 
                  'red' : '+/- 2 %', 
                 'green': "+/- 0.5 %", 
                  'blue': '+/- 0.25 %', 
                 'violet' : '+/- 0.1 %', 
                  'gold': '+/- 5 %', 
                 'silver' : '+/- 10 %', 
                  'none': '+/-20 %'}
      
    if a in color_digit
       and b in color_digit\
       and c in multiplier 
       and d in tolerance:
           xx = color_digit.get(a)
           yy = color_digit.get(b)
           zz = multiplier.get(c)
           aa = tolerance.get(d)
           print("Resistance = "+xx + yy+\
                 " x "+zz+" ohms "+aa)
    else:
        print("Invalid Colors")
          
# Driver Code
if __name__ == "__main__":
    a = "black"
    b = "brown"
    c = "red"
    d = "green"
      
    # Function Call
    findResistance(a, b, c, d)

输出：

Resistance = 01 x 100 ohms +/- 0.5 %

查找5频段电阻器电阻的程序

给定五个字符串A ， B ， C ， D和E ，它们表示5波段电阻器的颜色代码。任务是使用给定的颜色代码找到电阻，公差和瓦特数额定值。

例子：

Input: A = “black”, B = “brown”, C = “red”, D = “green”, E = “silver”
Output: Resistance = 012 x 100k ohms +/- 10 %

Input: A = “red”, B = “orange”, C = “yellow”, D = “green”, E = “gold”
Output: Resistance = 234 x 100k ohms +/- 5 %

方法：想法是将数字和乘法器存储在哈希图中，然后可以计算电阻器的电阻。

下面是上述方法的实现：

Python3

# Python implementation to find the 
# resistance of the resistor with
# the given color codes
  
# Function to find the resistance 
# using color codes
def findResistance(a, b, c, d, e):
      
    # Hash-map to store the values 
    # of the color-digits
    color_digit = {'black': '0',
                   'brown': '1', 
                   'red': '2',
                   'orange': '3', 
                   'yellow': '4',
                   'green' : '5', 
                   'blue' : '6',
                   'violet' : '7', 
                   'grey' : '8',
                   'white': '9'}
      
    multiplier = {'black': '1',
                  'brown': '10', 
                  'red': '100', 
                  'orange': '1k', 
                  'yellow': '10k', 
                  'green' : '100k', 
                  'blue' : '1M', 
                  'violet' : '10M', 
                  'grey' : '100M', 
                  'white': '1G'}
      
    tolerance = {'brown': '+/- 1 %', 
                  'red' : '+/- 2 %', 
                 'green': "+/- 0.5 %", 
                  'blue': '+/- 0.25 %', 
                 'violet' : '+/- 0.1 %', 
                  'gold': '+/- 5 %', 
                 'silver' : '+/- 10 %', 
                  'none': '+/-20 %'}
      
    if a in color_digit
       and b in color_digit\
       and c in color_digit
       and d in multiplier\
       and e in  tolerance:
           xx = color_digit.get(a)
           yy = color_digit.get(b)
           zz = color_digit.get(c)
           aa = multiplier.get(d)
           bb = tolerance.get(e)
           print("Resistance = "+xx + yy\
               + zz+" x "+aa+" ohms "+bb)
    else:
        print("Invalid Colors")
          
# Driver Code
if __name__ == "__main__":
    a = "red"
    b = "orange"
    c = "yellow"
    d = "green"
    e = "gold"
      
    # Function Call
    findResistance(a, b, c, d, e)

输出：

Resistance = 234 x 100k ohms +/- 5 %