和弦长度如果给定另一个和弦的直径相等的圆的直径，则为圆

给定两个和弦，它们在圆的直径上相等地倾斜。给出一个和弦的长度。任务是找到另一个和弦的长度。
例子：

Input: z = 48
Output: 48 degrees

Input: z = 93
Output: 93 degrees

方法：

• 令AB和AC为以O为中心的圆的两个和弦。
• 现在，在图中我们看到，
  OL垂直于AB ， OM垂直于AC
• 在三角形OLA和三角形OMA中，
  角度OLA =角度OMA = 90度
  角度OAL =角度OAM (因为弦在直径上相等地倾斜)
  OA = OA (公共端)
• 因此三角形OLA和三角形OMA是完全相同的。
• 因此， OL = OM
• 并且我们知道，相等的和弦与中心等距，因此AB和AC的长度相同。

If two chords are equally inclined through the diameter of the same circle, then they are of equal length.

下面是上述方法的实现：

C++

// C++ program to find
// the length of the chord the circle
// if length of the another chord
// which is equally inclined
// through the diameter is given
 
#include 
using namespace std;
 
void lengchord(int z)
{
    cout << "The length is "
         << z << endl;
}
 
// Driver code
int main()
{
    int z = 48;
    lengchord(z);
    return 0;
}

Java

// Java program to find
// the length of the chord the circle
// if length of the another chord
// which is equally inclined
// through the diameter is given
import java.io.*;
 
class GFG
{
     
static void lengchord(int z)
{
    System.out.println ("The length is "+ z );
}
 
// Driver code
public static void main (String[] args)
{
 
    int z = 48;
    lengchord(z);
}
}
 
// The code has been contributed by ajit.

Python3

# Python3 program to find
# the length of the chord of the circle
# if length of the other chord
# which is equally inclined
# through the diameter is given
def lengchord(z):
    print("The length is ", end = "");
    print(z);
 
# Driver code
z = 48;
lengchord(z);
 
# This code is contributed
# by Princi Singh

C#

// C# program to find
// the length of the chord the circle
// if length of the another chord
// which is equally inclined
// through the diameter is given
using System;
 
class GFG
{
         
static void lengchord(int z)
{
    Console.WriteLine("The length is "+ z );
}
 
// Driver code
static public void Main ()
{
         
    int z = 48;
    lengchord(z);
}
}
 
// The code has been contributed by Tushil

Javascript

 
// javascript program to find
// the length of the chord the circle
// if length of the another chord
// which is equally inclined
// through the diameter is given
 
 
function lengchord(z)
{
    document.write("The length is "+ z );
}
 
// Driver code
 
var z = 48;
lengchord(z);
 
// This code is contributed by Amit Katiyar
 

输出：

The length is 48