检查给定的圆是否完全位于由两个同心圆形成的圆环内

给定两个半径为r和R的圆，它们的圆心都在原点。现在，给定另一个半径为r1并以(x1，y1)为中心的圆。检查第三个圆(半径为r1的圆)是否完全位于由半径为r和R的两个圆形成的圆环内。
例子 ：

Input : r = 8 R = 4
        r1 = 2 x1 = 6 y1 = 0
Output : yes

Input : r = 8 R = 4 
        r1 = 2 x1 = 5 y1 = 0
Output : no

重要提示：同心圆是指具有相同中心的圆。位于两个同心圆之间的区域称为环或圆环。

例子 ：
有两个同心圆，其中心在原点(0，0)，半径为r = 8和R = 4。
1.)圆1和2位于圆环内。
2.)圈3和圈4在圈外。
完整的图形如下所示：

方法 ：
毕达哥拉斯定理可以解决这个问题。使用毕达哥拉斯(Pythagoras)定理计算圆心与原点之间的距离，假设它用“ dis”表示。
计算完距离后，只需检查(dis – r1)> = r和(dis + r1)<= R的值。如果这两个条件都成立，则圆完全位于圆环内。

C++

// CPP code to check if a circle
// lies in the ring
#include 
using namespace std;
 
// Function to check if circle
// lies in the ring
bool checkcircle(int r, int R, int r1,
                        int x1, int y1)
{
    // distance between center of circle
    // center of concentric circles(origin)
    // using Pythagoras theorem
    int dis = sqrt(x1*x1+y1*y1);
     
    // Condition to check if circle is
    // strictly inside the ring
    return (dis-r1 >= R && dis+r1 <= r);
}
 
// Driver Code
int main()
{
    // Both circle with radius 'r'
    // and 'R' have center (0,0)
    int r = 8, R = 4, r1 = 2, x1 = 6, y1 = 0;   
    if (checkcircle(r, R, r1, x1, y1))
       cout << "yes" << endl;
    else
       cout << "no" << endl;
     
    return 0;
}

Java

// Java code to check if a
// circle lies in the ring
import java.io.*;
 
class ring
{
    // Function to check if circle
    // lies in the ring
    public static boolean checkcircle(int r, int R,
                            int r1, int x1, int y1)
    {
        // distance between center of circle
        // center of concentric circles(origin)
        // using Pythagoras theorem
        int dis = (int)Math.sqrt(x1 * x1 +
                                 y1 * y1);
         
         // Condition to check if circle
         // is strictly inside the ring
        return (dis - r1 >= R && dis + r1 <= r);
    }
     
    // Driver Code
    public static void main(String args[])
    {
        // Both circle with radius 'r'
        // and 'R' have center (0,0)
        int r = 8, R = 4, r1 = 2, x1 = 6, y1 = 0;
        
        if (checkcircle(r, R, r1, x1, y1))
            System.out.println("yes");
        else
            System.out.println("no");
    }
}

Python3

# Python3 code to check if
# a circle  lies in the ring
import math
 
# Function to check if circle
# lies in the ring
def checkcircle(r, R, r1, x1, y1):
 
    # distance between center of circle
    # center of concentric circles(origin)
    # using Pythagoras theorem
    dis = int(math.sqrt(x1 * x1 + y1 * y1))
     
    # Condition to check if circle is
    # strictly inside the ring
    return (dis-r1 >= R and dis+r1 <= r)
 
 
# Driver Code
 
# Both circle with radius 'r'
# and 'R' have center (0,0)
r = 8; R = 4; r1 = 2; x1 = 6; y1 = 0
if (checkcircle(r, R, r1, x1, y1)):
    print("yes")
else:
    print("no")
     
# This code is contributed by Smitha Dinesh Semwal.

C#

// C# code to check if a
// circle lies in the ring
using System;
 
class ring {
     
    // Function to check if circle
    // lies in the ring
    public static bool checkcircle(int r, int R,
                         int r1, int x1, int y1)
    {
        // distance between center of circle
        // center of concentric circles(origin)
        // using Pythagoras theorem
        int dis = (int)Math.Sqrt(x1 * x1 + y1 * y1);
 
        // Condition to check if circle
        // is strictly inside the ring
        return (dis - r1 >= R && dis + r1 <= r);
    }
 
    // Driver Code
    public static void Main()
    {
        // Both circle with radius 'r'
        // and 'R' have center (0, 0)
        int r = 8, R = 4, r1 = 2, x1 = 6, y1 = 0;
 
        if (checkcircle(r, R, r1, x1, y1))
            Console.WriteLine("yes");
        else
            Console.WriteLine("no");
    }
}
 
// This code is contributed by vt_m.

PHP

= $R && $dis + $r1 <= $r);
}
 
    // Driver Code
    // Both circle with radius 'r'
    // and 'R' have center (0,0)
    $r = 8; $R = 4;
    $r1 = 2; $x1 = 6;
    $y1 = 0;
    if (checkcircle($r, $R, $r1, $x1, $y1))
     
    echo "yes" ,"\n";
    else
    echo "no" ,"\n";
     
// This code is contributed by ajit.
?>

Javascript

// JavaScript program code to check if a
// circle lies in the ring
 
// Function to check if circle
    // lies in the ring
    function checkcircle(r, R, r1, x1, y1)
    {
        // distance between center of circle
        // center of concentric circles(origin)
        // using Pythagoras theorem
        let dis = Math.sqrt(x1 * x1 +
                                 y1 * y1);
          
         // Condition to check if circle
         // is strictly inside the ring
        return (dis - r1 >= R && dis + r1 <= r);
    }
   
// Driver Code
 
        // Both circle with radius 'r'
        // and 'R' have center (0,0)
        let r = 8, R = 4, r1 = 2, x1 = 6, y1 = 0;
         
        if (checkcircle(r, R, r1, x1, y1))
            document.write("yes");
        else
            document.write("no");
 
// This code is contributed by splevel62.

输出：

yes

时间复杂度： O(1)

辅助空间： O(1)