平行四边形的对角线长度(使用边和另一对角线的长度)

给定两个整数A和B (分别表示平行四边形的长度)和整数D (代表对角线的长度)，任务是找到平行四边形的另一个对角线的长度。

例子：

Input: A = 10, B = 30, D = 20
Output: 40.0

Input: A = 6, B = 8, D = 10
Output: 10.0

方法：
对角线的平行四边形长度的边与对角线之间的关系由下式给出：

$Diagonal = \sqrt{2(a^2+b^2)-d^2}$

下面是上述方法的实现：

C++

// C++ Program to implement
// the above approach
#include 
using namespace std;
 
// Function to calculate the length
// of the diagonal of a parallelogram
// using two sides and other diagonal
float Length_Diagonal(int a, int b, int d)
{
 
    float diagonal = sqrt(2 * ((a * a) +
                               (b * b)) - (d * d));
 
    return diagonal;
}
 
// Driver Code
int main()
{
    int A = 10;
    int B = 30;
    int D = 20;
 
    // Function Call
    float ans = Length_Diagonal(A, B, D);
 
    // Print the final answer
    printf("%0.1f", ans);
    return 0;
}
 
// This code is contributed by Rohit_ranjan

Java

// Java Program to implement
// the above approach
class GFG{
 
// Function to calculate the length
// of the diagonal of a parallelogram
// using two sides and other diagonal
static float Length_Diagonal(int a, int b, int d)
{
 
    float diagonal = (float) Math.sqrt(2 * ((a * a) +
                                 (b * b)) - (d * d));
 
    return diagonal;
}
 
// Driver Code
public static void main(String[] args)
{
    int A = 10;
    int B = 30;
    int D = 20;
 
    // Function Call
    float ans = Length_Diagonal(A, B, D);
 
    // Print the final answer
    System.out.printf("%.1f", ans);
}
}
 
// This code is contributed by Rajput-Ji

Python

# Python Program to implement
# the above approach
 
import math
 
# Function to calculate the length
# of the diagonal of a parallelogram
# using two sides and other diagonal
def Length_Diagonal(a, b, d):
 
    diagonal = math.sqrt(2 * ((a**2) \
    + (b**2)) - (d**2))
 
    return diagonal
 
 
# Driver Code
A = 10
B = 30
D = 20
 
# Function Call
ans = Length_Diagonal(A, B, D)
 
# Print the final answer
print(round(ans, 2))

C#

// C# Program to implement
// the above approach
using System;
class GFG{
 
// Function to calculate the length
// of the diagonal of a parallelogram
// using two sides and other diagonal
static float Length_Diagonal(int a, int b, int d)
{
 
    float diagonal = (float) Math.Sqrt(2 * ((a * a) +
                                 (b * b)) - (d * d));
 
    return diagonal;
}
 
// Driver Code
public static void Main(String[] args)
{
    int A = 10;
    int B = 30;
    int D = 20;
 
    // Function Call
    float ans = Length_Diagonal(A, B, D);
 
    // Print the readonly answer
    Console.Write("{0:F1}", ans);
}
}
 
// This code is contributed by Rajput-Ji

Javascript

// javascript Program to implement
// the above approach
 
// Function to calculate the length
// of the diagonal of a parallelogram
// using two sides and other diagonal
function Length_Diagonal( a, b,  d)
{
 
    let diagonal = Math.sqrt(2 * ((a * a) +
                               (b * b)) - (d * d));
 
    return diagonal;
}
 
// Driver Code
    let A = 10;
    let B = 30;
    let D = 20;
 
    // Function Call
    let ans = Length_Diagonal(A, B, D);
 
    // Print the final answer
    document.write(ans.toFixed(1));
     
// This code is contributed by gauravrajput1

输出：

40.0

时间复杂度： O(1)
辅助空间： O(1)