检查大数是否可被20整除

给定一个数字，任务是检查数字是否可以被20整除。输入数字可能很大，可能无法存储long long int，并且它可能非常大，所以我们使用字符串。
例子：

Input : 7575680
Output : Yes

Input : 987985865687690
Output : No

如果数字可以被5和4整除，则数字可以被20整除。我们可以通过检查最后两位数是否可以被4整除来检查数字是否可以被4整除。可以通过检查最后一位数字来将数字整除为5。同样，如果数字的最后一位数字为零，而第二位最后一位数字为2的倍数，则该数字可被20整除。

C++

// CPP program to check if a large number
// is divisible by 20.
#include 
using namespace std;
 
bool divisibleBy20(string num)
{
    // Get number with last two digits
    int lastTwoDigits = stoi(num.substr(num.length() - 2,
                            num.length() - 1));
 
    // Check if the number formed by last two
    // digits is divisible by 5 and 4.
    return ((lastTwoDigits % 5 == 0) &&
            (lastTwoDigits % 4 == 0));
}
 
int main()
{
    string num = "63284689320";
    if (divisibleBy20(num))
        cout << "Yes" << endl;
    else
        cout << "No" << endl;
    return 0;
}

Java

// Java program to check if a large n
// number is divisible by 20.
import java.io.*;
 
class GFG {
     
    static Boolean divisibleBy20(String num)
    {
        // Get number with last two digits
        int lastTwoDigits = Integer.parseInt(num.substring(num.length() - 2,
                                                           num.length() ));
         
        // Check if the number formed by last two
        // digits is divisible by 5 and 4.
        return ((lastTwoDigits % 5 == 0) &&
                (lastTwoDigits % 4 == 0));
    }
     
    // Driver Program
    public static void main (String[] args)
    {
        String num = "63284689320";
        if (divisibleBy20(num) == true)
            System.out.println("Yes");
        else
            System.out.println("No");
         
    }
}
 
// This code is contributed by Gitanjali.

Python3

# Python3 program to check if a large
# number is divisible by 20.
import math
 
def divisibleBy20(num):
 
    # Get number with last two digits
    lastTwoDigits = int(num[-2:])
 
    # Check if the number formed by last two
    # digits is divisible by 5 and 4.
    return ((lastTwoDigits % 5 == 0 and
             lastTwoDigits % 4 == 0))
 
# driver code
num = "63284689320"
if (divisibleBy20(num) == True):
    print("Yes")
else:
    print("No")
 
# This code is contributed by Gitanjali.

C#

// C# program to check if a large
// 'n' number is divisible by 20.
using System;
using System.Text;
 
class GFG
{
 
static bool divisibleBy20(String num)
{
    // Get number with last two digits
    int lastTwoDigits = Int32.Parse(num.Substring(2));
     
    // Check if the number formed
    // by last two digits is
    // divisible by 5 and 4.
    return ((lastTwoDigits % 5 == 0) &&
            (lastTwoDigits % 4 == 0));
}
 
// Driver Code
static public void Main ()
{
    String num = "63284689320";
    if (divisibleBy20(num) == true)
        Console.Write("Yes");
    else
        Console.Write("No");
}
}
 
// This code is contributed by Raj

Javascript

// Javascript program to check
// if a large number is
// divisible by 20.
function divisibleBy20(num)
{
 
    // Get number with
    // last two digits
    let lastTwoDigits = parseInt(num.slice(-2, num.length))
    console.log(num.slice(-2, 1))
 
    // Check if the number
    // formed by last two
    // digits is divisible
    // by 5 and 4.
    return ((lastTwoDigits % 5 == 0) &&
            (lastTwoDigits % 4 == 0))
}
 
// Driver Code
let num = "63284689320";
if (divisibleBy20(num))
    document.write("Yes");
else
    document.write("No");
 
// This code is contributed by _saurabh_jaiswal.

输出：

Yes