找出系列0、6、0、12、0、90的N个项…

给定数字N。任务是编写一个程序来查找以下系列中的第N个术语：

0, 6, 0, 12, 0, 90…

例子：

Input : N = 4
Output : 12
For N = 4
Nth term = abs( 4 * ((4-1) * (4-3) * (4-5)) );
         = 12
Input : N = 6 
Output : 90

我们可以将上述系列的第N个术语概括为：

Nth term = abs( N * ((N-1) * (N-3) * (N-5)) )

下面是上述方法的实现：

C++

// CPP program to find N-th term of the series
// 0, 6, 0, 12, 0, 90...
 
#include 
using namespace std;
 
// Function to return the Nth term
int nthTerm(int N)
{
    return abs(N * ((N - 1) * (N - 3) * (N - 5)));
}
 
// Driver code
int main()
{
    int N = 6;
 
    cout << nthTerm(N);
 
    return 0;
}

Java

// Java program to find N-th term of the series
// 0, 6, 0, 12, 0, 90...
 
import java.io.*;
import java.lang.*;
 
class GFG {
    // Function to calculate Nth term of
    // the series
    public static int nthTerm(int N)
    {
        // By using above formula
        return Math.abs(N * ((N - 1) * (N - 3) * (N - 5)));
    }
     
    // Driver code
    public static void main(String[] args)
    {
        int N = 6; // Nth term is 6
        
        System.out.println(nthTerm(N));
    }
}

Python3

# Python3 program to find N-th
# term of the series
# 0, 6, 0, 12, 0, 90...
 
# Function to return the Nth term
def nthTerm(N) :
 
    return (abs(N * ((N - 1) * (N - 3)
           * (N - 5))))
 
# Driver code    
if __name__ == "__main__" :
 
    N = 6
 
    # Function calling
    print(nthTerm(N))
 
 
# This code is contributed by
# ANKITRAI1

C#

// C# program to find N-th term of the series
// 0, 6, 0, 12, 0, 90...
 
using System;
 
class GFG {
    // Function to calculate Nth term of
    // the series
    public static int nthTerm(int N)
    {
        // By using above formula
        return Math.Abs(N * ((N - 1) * (N - 3) * (N - 5)));
    }
     
    // Driver code
    public static void Main()
    {
        int N = 6; // Nth term is 6
         
        Console.WriteLine(nthTerm(N));
    }
}
// This code is contributed by anuj_67.

Javascript

// JavaScript  program to find N-th term of the series
// 0, 6, 0, 12, 0, 90...
 
// Function to return the Nth term
function nthTerm( N)
{
    return Math.abs(N * ((N - 1) * (N - 3) * (N - 5)));
}
 
// Driver code
 
    let N = 6;
   document.write( nthTerm(N) );
 
// This code contributed by aashish1995
 

输出：

90

时间复杂度：O(1)