Python|查找元组中的列表数量

给定一个列表元组，任务是找到一个元组中的列表数。这是一个非常基本的问题，但在制作一些实用程序时可能很有用。

方法 #1：使用len

# Python code to find number of list in a tuple
  
# Initial list 
Input1 = ([1, 2, 3, 4], [5, 6, 7, 8])
Input2 = ([1, 2], [3, 4], [5, 6])
Input3 = ([9, 8, 7, 6, 5, 4, 3, 2, 1], [1, 2, 3])
  
# Using len to find no of list in tuple
Output1 = len(Input1)
Output2 = len(Input2)
Output3 = len(Input3)
  
# Printing
print("Initial list :")
print(Input1)
print("No of list in tuples are :")
print(Output1)
print("\n")
  
print("Initial list :")
print(Input2)
print("No of list in tuples are :")
print(Output2)
print("\n")
  
  
print("Initial list :")
print(Input3)
print("No of list in tuples are :")
print(Output3)
print("\n")

输出：

Initial list :
([1, 2, 3, 4], [5, 6, 7, 8])
No of list in tuples are :
2


Initial list :
([1, 2], [3, 4], [5, 6])
No of list in tuples are :
3


Initial list :
([9, 8, 7, 6, 5, 4, 3, 2, 1], [1, 2, 3])
No of list in tuples are :
2

方法 #2：使用函数和 isinstance

# Python code to find number of list in a tuple
  
# Using find function
def find(Input):
    if isinstance(Input, list):
        return 1
    else:
        return len(Input)
  
# List initialization
Input1 = ([1, 2, 3, 4], [5, 6, 7, 8])
Input2 = ([1, 2], [3, 4], [5, 6])
Input3 = ([9, 8, 7, 6, 5, 4, 3, 2, 1])
  
# using find
Output1 = find(Input1)
Output2 = find(Input2)
Output3 = find(Input3)
  
# printing
print("Initial list :")
print(Input1)
print("No of list in tuples are :")
print(Output1)
print("\n")
  
print("Initial list :")
print(Input2)
print("No of list in tuples are :")
print(Output2)
print("\n")
  
  
print("Initial list :")
print(Input3)
print("No of list in tuples are :")
print(Output3)
print("\n")

输出：

Initial list :
([1, 2, 3, 4], [5, 6, 7, 8])
No of list in tuples are :
2


Initial list :
([1, 2], [3, 4], [5, 6])
No of list in tuples are :
3


Initial list :
[9, 8, 7, 6, 5, 4, 3, 2, 1]
No of list in tuples are :
1