可以刻在球体内的最大右圆锥

给定半径范围$r$ 。任务是找到基座的半径和可以在其中刻出的最大右圆锥形的高度。
例子：

Input : R = 10
Output : r = 9.42809, h = 13.3333

Input : R = 25
Output : r = 23.5702, h = 33.3333

方法：
令圆锥的半径= r
圆锥的高度= h
从图中可以清楚地看出：
x =√(R ^ 2 – r ^ 2)和h = x + R
现在使用这些值，

To maximize the volume of the cone(V): 
V = (πr²h)/3
From the diagram, 
V = (πr²R)/3 + πr²√(R² – r²)/3
Taking first derivative of V with respect to r we get, 
$dV/dr = 2\pi r(\sqrt(R^2 - r^2) + R)/3 - \frac{\pi r^3}{\sqrt(R^2 - r^2)}/3$
Now, setting dV/dr = 0 we get, 
$\frac{2\pi r}{3}[R+\sqrt(R^2-r^2)] =\frac{ \pi r^3}{3\sqrt(R^2 - r^2}$
$2[R+\sqrt(R^2-r^2)] =\frac{r^2}{\sqrt(R^2 - r^2)}$
$2R\sqrt(R^2 - r^2)}+2(R^2 - r^2)=r^2\scriptstyle\implies 2R\sqrt(R^2 - r^2)}=3r^2 - 2R^2$
Squaring both sides and solving we get, 
$9r^4=8r^2 R^2$
$r=\frac{2\sqrt{2}R}{3}$
since, h = R + √(R² – r²)
Now calculating the second derivative we get 

Thus r=(2R√2)/3 is point of maxima 
So, h = 4R/3 
 

下面是上述方法的实现：

C++

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Java

// C++ Program to find the biggest cone
// that can be inscribed within a sphere
#include 
using namespace std;
 
// Function to find the radius of the cone
float coner(float R)
{
 
    // radius cannot be negative
    if (R < 0)
        return -1;
 
    // radius of the cone
    float r = (2 * sqrt(2) * R) / 3;
    return r;
}
 
// Function to find the height of the cone
float coneh(float R)
{
 
    // side cannot be negative
    if (R < 0)
        return -1;
 
    // height of the cone
    float h = (4 * R) / 3;
    return h;
}
 
// Driver code
int main()
{
    float R = 10;
 
    cout << "r = " << coner(R) << ", "
         << "h = " << coneh(R) << endl;
 
    return 0;
}

Python3

// Java Program to find the biggest cone
// that can be inscribed within a sphere
import java.util.*;
import java.lang.*;
 
class GFG
{
// Function to find the radius
// of the cone
static float coner(float R)
{
    // radius cannot be negative
    if (R < 0)
        return -1;
 
    // radius of the cone
    float r = (float)(2 *
            Math.sqrt(2) * R) / 3;
    return r;
}
 
// Function to find the
// height of the cone
static float coneh(float R)
{
 
    // side cannot be negative
    if (R < 0)
        return -1;
 
    // height of the cone
    float h = (4 * R) / 3;
    return h;
}
 
// Driver code
public static void main(String args[])
{
    float R = 10;
 
    System.out.println("r = " + coner(R) +
                       ", " + "h = " + coneh(R));
}
}
 
// This code is contributed
// by Akanksha Rai

C#

# Python 3 Program to find the biggest cone
# that can be inscribed within a sphere
import math
 
# Function to find the radius
# of the cone
def coner(R):
     
    # radius cannot be negative
    if (R < 0):
        return -1;
     
    # radius of the cone
    r = (2 * math.sqrt(2) * R) / 3
    return float(r)
 
# Function to find the height
# of the cone
def coneh(R):
     
    # side cannot be negative
    if (R < 0):
        return -1;
 
    # height of the cone
    h = (4 * R) / 3
    return float(h)
 
# Driver code
R = 10
print("r = " , coner(R) ,
      ", ", "h = " , coneh(R))
 
# This code is contributed
# by 29AjayKumar

PHP

// C# Program to find the biggest cone
// that can be inscribed within a sphere
using System;
 
class GFG
{
// Function to find the radius
// of the cone
static float coner(float R)
{
    // radius cannot be negative
    if (R < 0)
        return -1;
 
    // radius of the cone
    float r = (float)(2 *
               Math.Sqrt(2) * R) / 3;
    return r;
}
 
// Function to find the
// height of the cone
static float coneh(float R)
{
 
    // side cannot be negative
    if (R < 0)
        return -1;
 
    // height of the cone
    float h = (4 * R) / 3;
    return h;
}
 
// Driver code
public static void Main()
{
    float R = 10;
 
    Console.WriteLine("r = " + coner(R) +
                      ", " + "h = " + coneh(R));
}
}
 
// This code is contributed
// by Akanksha Rai

输出：

// javascript Program to find the biggest cone
// that can be inscribed within a sphere
 
// Function to find the radius
// of the cone
function coner(R)
{
 
    // radius cannot be negative
    if (R < 0)
        return -1;
 
    // radius of the cone
    var r = (2 *
            Math.sqrt(2) * R) / 3;
    return r;
}
 
// Function to find the
// height of the cone
function coneh(R)
{
 
    // side cannot be negative
    if (R < 0)
        return -1;
 
    // height of the cone
    var h = (4 * R) / 3;
    return h;
}
 
// Driver code
var R = 10;
document.write("r = " + coner(R).toFixed(5) +
                   ", " + "h = " + coneh(R).toFixed(5));
 
// This code is contributed by 29AjayKumar