给定两个表示分数的分子和分母的整数，以字符串格式返回分数。如果小数部分是重复的，则将重复的部分括在括号中。
例子：
Input: Numerator = 1, Denominator = 2
Output: "0.5"
1/2 = 0.5 with no repeating part.
Input: Numerator = 50, Denominator = 22
Output: "2.(27)"
50/22 = 2.27272727... Since fractional part (27)
is repeating, it is enclosed in parentheses.先决条件：分数中的重复序列
方法：想法是首先计算积分商(小数点前的绝对部分)，然后计算小数部分。要检查小数部分是否重复，请在映射中插入余数(分子％分母)，其中键为余数，值为发生此余数的索引位置。如果在任何时间点，余数变为零，则不存在重复分数；否则，如果在映射中已找到余数，则存在重复分数。
下面是上述方法的实现。
C++
// C++ program to calculate
// fraction of two numbers
#include
using namespace std;
// Function to return the required fraction
// in string format
string calculateFraction(int num, int den)
{
// If the numerator is zero, answer is 0
if (num == 0)
return "0";
// If any one (out of numerator and denominator)
// is -ve, sign of resultant answer -ve.
int sign = (num < 0) ^ (den < 0) ? -1 : 1;
num = abs(num);
den = abs(den);
// Calculate the absolute part
// (before decimal point).
int initial = num / den;
// Output string to store the answer
string res;
// Append sign
if (sign == -1)
res += "-";
// Append the initial part
res += to_string(initial);
// If completely divisible, return answer.
if (num % den == 0)
return res;
res += ".";
// Initialize Remainder
int rem = num % den;
map mp;
// Position at which fraction starts repeating
// if it exists
int index;
bool repeating = false;
while (rem > 0 && !repeating) {
// If this remainder is already seen,
// then there exists a repeating fraction.
if (mp.find(rem) != mp.end()) {
// Index to insert parentheses
index = mp[rem];
repeating = true;
break;
}
else
mp[rem] = res.size();
rem = rem * 10;
// Calculate quotient, append
// it to result and
// calculate next remainder
int temp = rem / den;
res += to_string(temp);
rem = rem % den;
}
// If repeating fraction exists,
// insert parentheses.
if (repeating) {
res += ")";
res.insert(index, "(");
}
// Return result.
return res;
}
// Drivers Code
int main()
{
int num = 50, den = 22;
cout << calculateFraction(num, den) << endl;
num = -1, den = 2;
cout << calculateFraction(num, den) << endl;
return 0;
} Java
// Java program to calculate fraction
// of two numbers
import java.util.*;
class GFG {
// Function to return the required fraction
// in string format
public static String calculateFraction(int num, int den)
{
if (num == 0)
return "0"; // if numerator is zero
if (den == 0)
return ""; // if denominator is zero
// result StringBuilder
StringBuilder result = new StringBuilder();
if ((num < 0) ^ (den < 0))
result.append("-"); // check -ve sign
// absoulte values of num and den
num = Math.abs(num);
den = Math.abs(den);
long quo = num / den; // Quotient
long rem = num % den * 10; // calculating remainder
result.append(
String.valueOf(quo)); // appending quotient
if (rem == 0)
return result
.toString(); // return if remainder is 0
// if remainder is not zero, continue
result.append(".");
Map m
= new HashMap<>(); // map for storing remainder
// and the indexes of the
// appropriate decimal in
// stringbuilder
while (rem != 0) {
if (m.containsKey(rem)) {
// if the rem is already present, find the
// index and append ( )
int index = m.get(rem);
String part1 = result.substring(0, index);
String part2 = "("
+ result.substring(
index, result.length())
+ ")";
return part1 + part2;
}
// continue updating the map and appending quo
// which was generated by dividing rem with den
m.put(rem, result.length());
quo = rem / den;
result.append(String.valueOf(quo));
// update rem
rem = (rem % den) * 10;
}
return result.toString();
}
// Driver code
public static void main(String[] args)
{
int num = 113;
int den = 56;
String resString1 = calculateFraction(num, den);
num = -1;
den = 2;
String resString2 = calculateFraction(num, den);
System.out.println(resString1);
System.out.println(resString2);
}
}
// This code is contributed by Saiteja Marisetti Python3
# Python3 program to calculate fraction
# of two numbers
# Function to return the required
# fraction in string format
def calculateFraction(num, den) :
# If the numerator is zero, answer is 0
if (num == 0):
return "0"
# If any one (out of numerator and denominator)
# is -ve, sign of resultant answer -ve.
sign = -1 if (num < 0) ^ (den < 0) else 1
num = abs(num)
den = abs(den)
# Calculate the absolute part
# (before decimal point).
initial = num // den
# Output string to store the answer
res = ""
# Append sign
if (sign == -1):
res += "-"
# Append the initial part
res += str(initial)
# If completely divisible, return answer.
if (num % den == 0):
return res
res += "."
# Initialize Remainder
rem = num % den
mp = {}
# Position at which fraction starts
# repeating if it exists
index = 0
repeating = False
while (rem > 0 and not repeating) :
# If this remainder is already seen,
# then there exists a repeating fraction.
if ( rem in mp):
# Index to insert parentheses
index = mp[rem]
repeating = True
break
else:
mp[rem] = len(res)
rem = rem * 10
# Calculate quotient, append it to result
# and calculate next remainder
temp = rem // den
res += str(temp )
rem = rem % den
# If repeating fraction exists,
# insert parentheses.
if (repeating) :
res += ")"
x = res[:index]
x += "("
x += res[index:]
res = x
# Return result.
return res
# Driver code
if __name__ =="__main__":
num = 50
den = 22
print(calculateFraction(num, den))
num = -1
den = 2
print(calculateFraction(num, den))
# This code is contributed
# Shubham Singh(SHUBHAMSINGH10)输出：
2.(27)
-0.5