数组中两个元素之间的最大差

给定N个整数的数组arr [] ，任务是查找数组中任何两个元素之间的最大差。

例子：

Input: arr[] = {2, 1, 5, 3}
Output: 4
|5 – 1| = 4

Input: arr[] = {-10, 4, -9, -5}
Output: 14

方法：数组中的最大绝对差将始终是数组中最小和最大元素之间的绝对差。

下面是上述方法的实现：

C++

// C++ implementation of the approach
#include 
using namespace std;
  
// Function to return the maximum
// absolute difference between
// any two elements of the array
int maxAbsDiff(int arr[], int n)
{
  
    // To store the minimum and the maximum
    // elements from the array
    int minEle = arr[0];
    int maxEle = arr[0];
    for (int i = 1; i < n; i++) {
        minEle = min(minEle, arr[i]);
        maxEle = max(maxEle, arr[i]);
    }
  
    return (maxEle - minEle);
}
  
// Driver code
int main()
{
    int arr[] = { 2, 1, 5, 3 };
    int n = sizeof(arr) / sizeof(arr[0]);
    cout << maxAbsDiff(arr, n);
  
    return 0;
}

Java

// Java implementation of the approach
class GFG {
  
    // Function to return the maximum
    // absolute difference between
    // any two elements of the array
    static int maxAbsDiff(int arr[], int n)
    {
  
        // To store the minimum and the maximum
        // elements from the array
        int minEle = arr[0];
        int maxEle = arr[0];
        for (int i = 1; i < n; i++) {
            minEle = Math.min(minEle, arr[i]);
            maxEle = Math.max(maxEle, arr[i]);
        }
  
        return (maxEle - minEle);
    }
  
    // Driver code
    public static void main(String[] args)
    {
        int[] arr = { 2, 1, 5, 3 };
        int n = arr.length;
        System.out.print(maxAbsDiff(arr, n));
    }
}

Python3

# Python3 implementation of the approach
  
# Function to return the maximum
# absolute difference between
# any two elements of the array
def maxAbsDiff(arr, n):
  
    # To store the minimum and the maximum
    # elements from the array
    minEle = arr[0]
    maxEle = arr[0]
    for i in range(1, n):
        minEle = min(minEle, arr[i])
        maxEle = max(maxEle, arr[i])
  
    return (maxEle - minEle)
  
# Driver code
arr = [2, 1, 5, 3]
n = len(arr)
print(maxAbsDiff(arr, n))
  
# This code is contributed 
# by mohit kumar

C#

// C# implementation of the approach 
using System;
  
class GFG
{ 
  
    // Function to return the maximum 
    // absolute difference between 
    // any two elements of the array 
    static int maxAbsDiff(int []arr, int n) 
    { 
  
        // To store the minimum and the maximum 
        // elements from the array 
        int minEle = arr[0]; 
        int maxEle = arr[0]; 
        for (int i = 1; i < n; i++) 
        { 
            minEle = Math.Min(minEle, arr[i]); 
            maxEle = Math.Max(maxEle, arr[i]); 
        } 
  
        return (maxEle - minEle); 
    } 
  
    // Driver code 
    public static void Main() 
    { 
        int[] arr = { 2, 1, 5, 3 }; 
        int n = arr.Length; 
          
        Console.WriteLine(maxAbsDiff(arr, n)); 
    } 
} 
  
// This code is contributed by Ryuga

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输出：

4