N阶图中的像元数

给定整数N ，任务是查找给定类型的^第N^个阶图中的像元数：

例子：

Input: N = 2 
Output: 5
Input: N = 3 
Output: 13 
 

方法：可以观察到，对于N = 1，2，3，…的序列将形成为1，5，13，25，41，61，85，113，145，181，…，其^第N^个项将是N ² +(N – 1) ² 。
下面是上述方法的实现：

C++

// C++ implementation of the approach
#include 
using namespace std;
 
// Function to return the number
// of cells in the nth order
// figure of the given type
int cntCells(int n)
{
    int cells = pow(n, 2) + pow(n - 1, 2);
    return cells;
}
 
// Driver code
int main()
{
    int n = 3;
 
    cout << cntCells(n);
 
    return 0;
}

Java

// Java implementation of the approach
class GFG
{
     
// Function to return the number
// of cells in the nth order
// figure of the given type
static int cntCells(int n)
{
    int cells = (int)Math.pow(n, 2) +
                (int)Math.pow(n - 1, 2);
    return cells;
}
 
// Driver code
public static void main(String[] args)
{
    int n = 3;
 
    System.out.println(cntCells(n));
}
}
 
// This code is contributed by Code_Mech

Python3

# Python3 implementation of the approach
 
# Function to return the number
# of cells in the nth order
# figure of the given type
def cntCells(n) :
 
    cells = pow(n, 2) + pow(n - 1, 2);
     
    return cells;
 
# Driver code
if __name__ == "__main__" :
 
    n = 3;
 
    print(cntCells(n));
 
# This code is contributed by AnkitRai01

C#

// C# implementation of the approach
using System;
     
class GFG
{
     
// Function to return the number
// of cells in the nth order
// figure of the given type
static int cntCells(int n)
{
    int cells = (int)Math.Pow(n, 2) +
                (int)Math.Pow(n - 1, 2);
    return cells;
}
 
// Driver code
public static void Main(String[] args)
{
    int n = 3;
 
    Console.WriteLine(cntCells(n));
}
}
 
// This code is contributed by 29AjayKumar

Javascript

 
// Javascript implementation of the approach
 
// Function to return the number
// of cells in the nth order
// figure of the given type
function cntCells(n)
{
    var cells = Math.pow(n, 2) + Math.pow(n - 1, 2);
    return cells;
}
 
// Driver code
var n = 3;
document.write(cntCells(n));
 
 

输出：

13