删除字符串所有出现的字符

给定一个字符串。编写一个程序来删除字符串中所有出现的字符。
例子：

Input : s = "geeksforgeeks"
        c = 'e'
Output : s = "gksforgks"


Input : s = "geeksforgeeks"
        c = 'g'
Output : s = "eeksforeeks"

这个想法是维护结果字符串的索引。

C++

// C++ program to remove a particular character
// from a string.
#include 
using namespace std;
 
void removeChar(char* s, char c)
{
 
    int j, n = strlen(s);
    for (int i = j = 0; i < n; i++)
        if (s[i] != c)
            s[j++] = s[i];
 
    s[j] = '\0';
}
 
int main()
{
    char s[] = "geeksforgeeks";
    removeChar(s, 'g');
    cout << s;
    return 0;
}

Java

// Java program to remove
// a particular character
// from a string.
class GFG
{
static void removeChar(String s, char c)
{
    int j, count = 0, n = s.length();
    char []t = s.toCharArray();
    for (int i = j = 0; i < n; i++)
    {
        if (t[i] != c)
        t[j++] = t[i];
        else
            count++;
    }
     
    while(count > 0)
    {
        t[j++] = '\0';
        count--;
    }
     
    System.out.println(t);
}
 
// Driver Code
public static void main(String[] args)
{
    String s = "geeksforgeeks";
    removeChar(s, 'g');
}
}
 
// This code is contributed
// by ChitraNayal

Python3

# Python3 program to remove
# a particular character
# from a string.
 
# function for removing the
# occurrence of character
def removeChar(s, c) :
     
    # find total no. of
    # occurrence of character
    counts = s.count(c)
 
    # convert into list
    # of characters
    s = list(s)
 
    # keeep looping untill
    # counts become 0
    while counts :
         
        # remove character
        # from the list
        s.remove(c)
 
        # decremented by one
        counts -= 1
 
    # join all remaining characters
    # of the list with empty string
    s = '' . join(s)
     
    print(s)
 
# Driver code
if __name__ == '__main__' :
     
    s = "geeksforgeeks"
    removeChar(s,'g')
     
# This code is contributed
# by Ankit Rai

C#

// C# program to remove a
// particular character
// from a string.
using System;
 
class GFG
{
static void removeChar(string s,
                       char c)
{
    int j, count = 0, n = s.Length;
    char[] t = s.ToCharArray();
    for (int i = j = 0; i < n; i++)
    {
        if (s[i] != c)
        t[j++] = s[i];
        else
            count++;
    }
     
    while(count > 0)
    {
        t[j++] = '\0';
        count--;
    }
     
    Console.Write(t);
}
 
// Driver Code
public static void Main()
{
    string s = "geeksforgeeks";
    removeChar(s, 'g');
}
}
 
// This code is contributed
// by ChitraNayal

输出：

eeksforeeks

时间复杂度： O(n)，其中n是输入字符串的长度。
辅助空间： O(1)