检查浮点值是否等于整数值

给定浮点数N ，任务是检查N的值是否等于整数。如果发现是真的，则打印“是” 。否则，打印“否” 。

例子：

Input: N = 1.5
Output: NO

Input: N = 1.0
Output: YES

方法：想法是使用类型转换的概念。请按照以下步骤解决问题：

• 初始化一个变量，例如X ，以存储N的整数值。
• 将N的float值转换为整数，并将其存储在X中。
• 最后，检查(N – X)是否大于0 。如果发现是真的，则打印“否” 。
• 否则，打印“是” 。

下面是上述方法的实现：

C++

// C++ program to implement
// the above approach
 
#include 
using namespace std;
 
// Function to check if N is
// equivalent to an integer
bool isInteger(double N)
{
 
    // Convert float value
    // of N to integer
    int X = N;
 
    double temp2 = N - X;
 
    // If N is not equivalent
    // to any integer
    if (temp2 > 0) {
        return false;
    }
    return true;
}
 
// Driver Code
int main()
{
    double N = 1.5;
 
    if (isInteger(N)) {
 
        cout << "YES";
    }
    else {
 
        cout << "NO";
    }
 
    return 0;
}

Java

// Java program to implement
// the above approach
import java.util.*;
class GFG
{
     
// Function to check if N is
// equivalent to an integer
static boolean isInteger(double N)
{
 
    // Convert float value
    // of N to integer
    int X = (int)N;
    double temp2 = N - X;
 
    // If N is not equivalent
    // to any integer
    if (temp2 > 0)
    {
        return false;
    }
    return true;
}
   
// Driver code
public static void main(String[] args)
{
    double N = 1.5;
    if (isInteger(N))
    {
        System.out.println("YES");
    }
    else
    {
        System.out.println("NO");
    }
}
}
 
// This code is contributed by susmitakundugoaldanga

Python3

# Python3 program to implement
# the above approach
 
# Function to check if N is
# equivalent to an integer
def isInteger(N):
   
    # Convert float value
    # of N to integer
    X = int(N)
 
    temp2 = N - X
 
    # If N is not equivalent
    # to any integer
    if (temp2 > 0):
        return False
         
    return True
 
# Driver Code
if __name__ == '__main__':
     
    N = 1.5
     
    if (isInteger(N)):
        print("YES")
    else:
        print("NO")
 
# This code is contributed by mohit kumar 29

C#

// C# program to implement
// the above approach
using System;
 
class GFG{
     
// Function to check if N is
// equivalent to an integer
static bool isint(double N)
{
     
    // Convert float value
    // of N to integer
    int X = (int)N;
     
    double temp2 = N - X;
 
    // If N is not equivalent
    // to any integer
    if (temp2 > 0)
    {
        return false;
    }
    return true;
}
   
// Driver code
public static void Main(String[] args)
{
    double N = 1.5;
     
    if (isint(N))
    {
        Console.WriteLine("YES");
    }
    else
    {
        Console.WriteLine("NO");
    }
}
}
 
// This code is contributed by 29AjayKumar

输出：

NO

时间复杂度： O(1)
辅助空间： O(1)