检查十六进制十进制数是偶数还是奇数

给定十六进制十进制数，请检查它是偶数还是奇数。

例子：

Input: N = ABC7787CC87AA
Output: Even

Input: N = 9322DEFCD
Output: Odd

天真的方法：

• 将数字从十六进制基数转换为十进制基数。
• 然后检查数字是偶数还是奇数，将其除以2即可轻松进行检查。

时间复杂度： O(N)

高效的方法：由于十六进制数字包含从0到15的数字，因此我们可以简单地检查最后一个数字是否为’0’，’2’，’4’，’6’，’8’，’A’(= 10 )，’C’(= 12)或’E’(= 14) 。如果是，则给定的十六进制十进制数将为偶数，否则为奇数。

下面是上述方法的实现。

C++

// C++ code to check if a HexaDecimal
// number is Even or Odd
  
#include 
using namespace std;
  
// Check if the number is odd or even
string even_or_odd(string N)
{
    int len = N.size();
  
    // check if the last digit
    // is either '0', '2', '4',
    // '6', '8', 'A'(=10),
    // 'C'(=12) or 'E'(=14)
    if (N[len - 1] == '0'
        || N[len - 1] == '2'
        || N[len - 1] == '4'
        || N[len - 1] == '6'
        || N[len - 1] == '8'
        || N[len - 1] == 'A'
        || N[len - 1] == 'C'
        || N[len - 1] == 'E')
        return ("Even");
    else
        return ("Odd");
}
  
// Driver code
int main()
{
    string N = "AB3454D";
  
    cout << even_or_odd(N);
  
    return 0;
}

Java

// Java code to check if a HexaDecimal
// number is Even or Odd
class GFG{
   
// Check if the number is odd or even
static String even_or_odd(String N)
{
    int len = N.length();
   
    // check if the last digit
    // is either '0', '2', '4',
    // '6', '8', 'A'(=10),
    // 'C'(=12) or 'E'(=14)
    if (N.charAt(len - 1) == '0'
        || N.charAt(len - 1) == '2'
        || N.charAt(len - 1) == '4'
        || N.charAt(len - 1) == '6'
        || N.charAt(len - 1) == '8'
        || N.charAt(len - 1) == 'A'
        || N.charAt(len - 1) == 'C'
        || N.charAt(len - 1) == 'E')
        return ("Even");
    else
        return ("Odd");
}
   
// Driver code
public static void main(String[] args)
{
    String N = "AB3454D";
    System.out.print(even_or_odd(N));
}
}
  
// This code is contributed by 29AjayKumar

Python 3

# Python code to check if a HexaDecimal
# number is Even or Odd
  
# Check if the number is odd or even
def even_or_odd(N):
    l = len(N)
  
    # check if the last digit
    # is either '0', '2', '4',
    # '6', '8', 'A'(=10),
    # 'C'(=12) or 'E'(=14)
    if (N[l - 1] == '0'or N[l - 1] == '2'or 
        N[l - 1] == '4'or N[l - 1] == '6'or 
        N[l - 1] == '8'or N[l - 1] == 'A'or 
        N[l - 1] == 'C'or N[l - 1] == 'E'):
        return ("Even")
    else:
        return ("Odd")
  
# Driver code
N = "AB3454D"
  
print(even_or_odd(N))
  
# This code is contributed by Atul_kumar_Shrivastava

C#

// C# code to check if a HexaDecimal
// number is Even or Odd
using System;
  
public class GFG{
  
    // Check if the number is odd or even
    static string even_or_odd(string N)
    {
        int len = N.Length;
      
        // check if the last digit
        // is either '0', '2', '4',
        // '6', '8', 'A'(=10),
        // 'C'(=12) or 'E'(=14)
        if (N[len - 1] == '0'
            || N[len - 1] == '2'
            || N[len - 1] == '4'
            || N[len - 1] == '6'
            || N[len - 1] == '8'
            || N[len - 1] == 'A'
            || N[len - 1] == 'C'
            || N[len - 1] == 'E')
            return ("Even");
        else
            return ("Odd");
    }
      
    // Driver code
    static public void Main ()
    {
        string N = "AB3454D";
      
        Console.WriteLine(even_or_odd(N));
    }
}
  
// This code is contributed by shubhamsingh10

输出：

Odd