Demlo数(平方数11…1)

给定一个数字，形式为11..1，使得其中的数字位数小于10，请找到该数字的平方。

例子：

Input : 111111
Output : 12345654321

Input : 1111
Output : 1234321

11…1(长度小于10)的平方称为Demlo数。 demlo数字是由1、2、3….n，n-1，n-2，…..1组成的数字。
Demlo编号为：

1 = 1
11 * 11 = 121
111 * 111 = 12321
1111 * 1111 = 1234321

为了找到定额数，首先我们找到增加的n个数字，然后再减少的n个数字。

C++

// CPP program to print DemloNumber
#include 
using namespace std;
  
// To return demlo number. This function assumes
// that the length of str is smaller than 10.
string printDemlo(string str)
{
    int len = str.length();
    string res = "";
  
    // Add numbers to res upto size
    // of str and then add number
    // reverse to it
    for (int i = 1; i <= len; i++)
        res += char(i + '0');
  
    for (int i = len - 1; i >= 1; i--)
        res += char(i + '0');
  
    return res;
}
  
// Driver program to test printDemlo()
int main()
{
    string str = "111111";
    cout << printDemlo(str);
    return 0;
}

Java

// Java program to print DemloNumber
public class Main {
  
    // To return demlo number. This function assumes
    // that the length of str is smaller than 10.
    static String printDemlo(String str)
    {
        int len = str.length();
        String res = "";
  
        // Add numbers to res upto size
        // of str and then add number
        // reverse to it
        for (int i = 1; i <= len; i++)
            res += Integer.toString(i);
  
        for (int i = len - 1; i >= 1; i--)
            res += Integer.toString(i);
  
        return res;
    }
  
    // Driver program to test printDemlo()
    public static void main(String[] args)
    {
        String str = "111111";
        System.out.println(printDemlo(str));
    }
}

Python

# Python program to print Demlo Number
  
# To return demlo number
# Length of s is smaller than 10
def printDemlo(s):
    l = len(s)
    res = ""
      
    # Add numbers to res upto size
    # of s then add in reverse
      
    for i in range(1,l+1):
        res = res + str(i)
      
    for i in range(l-1,0,-1):
        res = res + str(i)
      
    return res
      
  
# Driver Code
s = "111111"    
print printDemlo(s)
  
# Contributed by Harshit Agrawal

C#

// C# program to print DemloNumber
using System;
public class GFG {
  
    // To return demlo number. This function assumes
    // that the length of str is smaller than 10.
    static String printDemlo(String str)
    {
        int len = str.Length;
        String res = "";
  
        // Add numbers to res upto size
        // of str and then add number
        // reverse to it
        for (int i = 1; i <= len; i++)
            res += i.ToString();
  
        for (int i = len - 1; i >= 1; i--)
            res += i.ToString();
  
        return res;
    }
  
    // Driver program to test printDemlo()
    public static void Main()
    {
        String str = "111111";
        Console.WriteLine(printDemlo(str));
    }
}
// This code is contributed by mits

PHP

= 1; $i--)
        $res .= chr($i + 48);
  
    return $res;
}
  
// Driver Code
$str = "111111";
echo printDemlo($str);
  
// This code is contributed by mits
?>

输出：

12345654321