查找装满水箱后浪费的水量

给定水箱的容积V (以升为单位)。有一个泵以每分钟M升的速度向油箱加油。水箱底部有泄漏，以每分钟N升的速度浪费水。给定N小于M。任务是计算如果在装满水箱后看到泄漏，将浪费多少水。

例子：

Input : V = 700, M = 10, N = 3
Output : 300

Input : V = 1000, M = 100, N = 50
Output : 1000

方法：给定加油泵的速度为每分钟M升。因此，一分钟内充满的水量为M升。而且，一分钟内会浪费掉N升的水。因此，一分钟后，水箱中的水量将为(M – N)。因此，将油箱充满泄漏所需的总时间为V /(MN)。

因此，浪费的水量为(V /(MN))*N。

下面是上述方法的实现：

C++

// C++ program to find the volume of water wasted
  
#include 
using namespace std;
  
// Function to calculate amount of wasted water
double wastedWater(double V, double M, double N)
{
    double wasted_amt, amt_per_min, time_to_fill;
  
    // filled amount of water in one minute
    amt_per_min = M - N;
  
    // total time taken to fill the tank
    // because of leakage
    time_to_fill = V / amt_per_min;
  
    // wasted amount of water
    wasted_amt = N * time_to_fill;
  
    return wasted_amt;
}
  
// Driver code
int main()
{
    double V, M, N;
    V = 700;
    M = 10;
    N = 3;
    cout << wastedWater(V, M, N) << endl;
  
    V = 1000;
    M = 100;
    N = 50;
    cout << wastedWater(V, M, N) << endl;
  
    return 0;
}

Java

// Java program to find the 
// volume of water wasted
class GFG
{
      
// Function to calculate amount of wasted water
static double wastedWater(double V, double M, double N)
{
    double wasted_amt, amt_per_min, time_to_fill;
  
    // filled amount of water in one minute
    amt_per_min = M - N;
  
    // total time taken to fill the tank
    // because of leakage
    time_to_fill = V / amt_per_min;
  
    // wasted amount of water
    wasted_amt = N * time_to_fill;
  
    return wasted_amt;
}
  
// Driver code
public static void main(String[] args)
{
    double V, M, N;
    V = 700;
    M = 10;
    N = 3;
    System.out.println(wastedWater(V, M, N)) ;
  
    V = 1000;
    M = 100;
    N = 50;
    System.out.println(wastedWater(V, M, N));
}
}
  
// This Code is Contributed by Code_Mech.

Python3

# Python3 program to find the volume 
# of water wasted
  
# Function to calculate amount 
# of wasted water
def wastedWater(V, M, N):
  
    # filled amount of water in one minute
    amt_per_min = M - N
  
    # total time taken to fill the tank
    # because of leakage
    time_to_fill = V / amt_per_min
  
    # wasted amount of water
    wasted_amt = N * time_to_fill
  
    return wasted_amt
  
# Driver code
V = 700
M = 10
N = 3
print(wastedWater(V, M, N))
  
V = 1000
M = 100
N = 50
print(wastedWater(V, M, N))
  
# This code is contributed by Shrikant13

C#

// C# program to find the 
// volume of water wasted
using System;
  
class GFG
{
          
    // Function to calculate amount of wasted water
    static double wastedWater(double V, double M, double N)
    {
        double wasted_amt, amt_per_min, time_to_fill;
      
        // filled amount of water in one minute
        amt_per_min = M - N;
      
        // total time taken to fill the tank
        // because of leakage
        time_to_fill = V / amt_per_min;
      
        // wasted amount of water
        wasted_amt = N * time_to_fill;
      
        return wasted_amt;
    }
      
    // Driver code
    public static void Main()
    {
        double V, M, N;
        V = 700;
        M = 10;
        N = 3;
        Console.WriteLine(wastedWater(V, M, N)) ;
      
        V = 1000;
        M = 100;
        N = 50;
        Console.WriteLine(wastedWater(V, M, N));
    }
}
  
// This Code is Contributed by ihritik

输出：

300
1000