用于打印链接列表的反向而不实际反转的 C# 程序

给定一个链表，使用递归函数打印它的反向。例如，如果给定的链表是 1->2->3->4，那么输出应该是 4->3->2->1。
请注意，问题只是关于打印反向。要反转列表本身，请参阅此
难度级别：新手

算法：

printReverse(head)
  1. call print reverse for head->next
  2. print head->data

执行：

C#

// C# program to print reverse 
// of a linked list
using System;
  
public class LinkedList
{
    // Head of list
    Node head; 
  
    // Linked list Node
    class Node
    {
        public int data;
        public Node next;
        public Node(int d) 
        {
            data = d; next = null;
        }
    }
  
    // Function to print reverse 
    // of linked list 
    void printReverse(Node head)
    {
        if (head == null) return;
  
        // print list of head node
        printReverse(head.next);
  
        // After everything else is printed
        Console.Write(head.data + " ");
    }
  
    // Utility Functions 
  
    // Inserts a new Node at front 
    // of the list. 
    public void push(int new_data)
    {
        /* 1 & 2: Allocate the Node &
                  Put in the data*/
        Node new_node = new Node(new_data);
  
        // 3. Make next of new Node as head 
        new_node.next = head;
  
        // 4. Move the head to point to 
        // new Node 
        head = new_node;
    }
  
    // Driver code
    public static void Main(String []args)
    {
        // Let us create linked list 1->2->3->4
        LinkedList llist = new LinkedList();
        llist.push(4);
        llist.push(3);
        llist.push(2);
        llist.push(1);
  
        llist.printReverse(llist.head);
    }
}
// This code is contributed by Rajput-Ji

输出：

4 3 2 1

时间复杂度： O(n)

有关详细信息，请参阅有关打印链接列表的反向而不实际反转的完整文章！