Python|在两个列表中的同一索引上查找不匹配项

给定两个整数列表，任务是找到两个列表的元素不匹配的索引。

Input:
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]

Output: [1, 3]
Explanation:
At index=1 we have 2 and 5 and at index=3
we have 4 and 6 which mismatches.

以下是实现此任务的一些方法。
方法#1：使用迭代

Python3

# Python code to find the index at which the
# element of two list doesn't match.
 
# List initialisation
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]
 
# Index initialisation
y = 0
 
# Output list initialisation
Output = []
 
# Using iteration to find
for x in Input1:
    if x != Input2[y]:
        Output.append(y)
    y = y + 1
 
# Printing output
print(Output)

输出：

[1, 3]

方法 #2：使用列表理解和 zip

Python3

# Python code to find the index at which the
# element of two list doesn't match.
 
# List initialisation
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]
 
# Using list comprehension and zip
Output = [Input2.index(y) for x, y in
       zip(Input1, Input2) if y != x]
 
# Printing output
print(Output)

输出：

[1, 3]

方法#3：使用枚举

Python3

# Python code to find the index at which the
# element of two list doesn't match.
 
# List initialisation
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]
 
# Using list comprehension and enumerate
Output = [index for index, elem in enumerate(Input2)
                           if elem != Input1[index]]
 
# Printing output
print(Output)

输出：

[1, 3]