Java中的 BigInteger mod() 方法

Java.math.BigInteger.mod(BigInteger big)方法返回一个BigInteger，它的值等于(this BigInteger modfunction big(BigInteger pass as parameter))。换句话说，我们可以说这个方法在执行后返回值(this % big) step.mod 操作找到这个 BigInteger 除以另一个作为参数传递的 BigInteger 后的余数。

Java.math.BigInteger.mod(BigInteger big) 和Java.math.BigInteger.remainder(BigInteger val) 两个函数都找到余数，但 mod 操作总是返回非负 BigInteger。

句法：

public BigInteger mod(BigInteger big)

参数：该函数接受一个强制参数big ，它指定了我们想要分割这个 bigInteger 对象的 BigInteger 对象。

返回值：该方法返回与此 BigInteger mod big 相等的 BigInteger（BigInteger 作为参数传递）。

异常：该方法在big ≤ 0时抛出ArithmeticException

例子：

Input: BigInteger1=321456, BigInteger2=31711
Output: 4346
Explanation: BigInteger1.mod(BigInteger2)=4346. The divide operation between 
321456 and 31711 returns 4346 as remainder.

Input: BigInteger1=59185482345, BigInteger2=59185482345
Output: 0
Explanation: BigInteger1.mod(BigInteger2)=0. The divide operation between 
59185482345 and 59185482345 returns 0 as remainder.

下面的程序说明了 BigInteger 类的 mod() 方法：

示例 1：

// Java program to demonstrate mod() method of BigInteger
  
import java.math.BigInteger;
  
public class GFG {
  
    public static void main(String[] args)
    {
  
        // Creating 2 BigInteger objects
        BigInteger b1, b2;
  
        b1 = new BigInteger("321456");
        b2 = new BigInteger("31711");
  
        // apply mod() method
        BigInteger result = b1.mod(b2);
  
        // print result
        System.out.println("Result of mod 
                 operation between " + b1
                 + " and " + b2 +
                 " equal to " + result);
    }
}

输出：

Result of mod operation between 321456 and 31711 equal to 4346

示例 2：当两者的价值相等时。

// Java program to demonstrate mod() method of BigInteger
  
import java.math.BigInteger;
  
public class GFG {
  
    public static void main(String[] args)
    {
  
        // Creating 2 BigInteger objects
        BigInteger b1, b2;
  
        b1 = new BigInteger("3515219485");
        b2 = new BigInteger("3515219485");
  
        // apply mod() method
        BigInteger result = b1.mod(b2);
  
        // print result
        System.out.println("Result of mod 
                 operation between " + b1
                 + " and " + b2 +
                 " equal to " + result);
    }
}

输出：

Result of mod operation between 3515219485 and 3515219485 equal to 0

示例 3：当作为参数传递的 BigInteger 小于零时，程序显示异常。

// Java program to demonstrate mod() method of BigInteger
  
import java.math.BigInteger;
  
public class GFG {
  
    public static void main(String[] args)
    {
  
        // Creating 2 BigInteger objects
        BigInteger b1, b2;
  
        b1 = new BigInteger("3515219485");
        b2 = new BigInteger("-1711");
  
        // apply mod() method
        BigInteger result = b1.mod(b2);
  
        // print result
        System.out.println("Result of mod 
                 operation between " + b1
                 + " and " + b2 +
                 " equal to " + result);
    }
}

输出：

Exception in thread "main" java.lang.ArithmeticException: BigInteger: modulus not positive
    at java.math.BigInteger.mod(BigInteger.java:2458)
    at GFG.main(GFG.java:17)

参考： https: Java Java)