📜  如何在 C++ STL 中使用列表实现堆栈

📅  最后修改于: 2022-05-13 01:55:26.252000             🧑  作者: Mango

如何在 C++ STL 中使用列表实现堆栈

在本文中,我们将讨论如何在 C++ STL 中使用列表来实现堆栈。

堆栈是一种线性数据结构。 LIFO(后进先出)或 FILO(先进后出)。主要支持4大操作:
1. Push:将一个元素压入栈中。
2.弹出:按照LIFO顺序删除元素。
3. Top:返回栈顶元素。
4. Empty:返回栈是否为空。

下面是上述方法的实现:

C++
// C++ implementation of stack
// using list STL
#include 
using namespace std;
  
template 
// templating it so that any data type can be used
  
class Stack {
public:
    list l;
    int cs = 0;
    // current size of the stack
  
    // pushing an element into the stack
    void push(T d)
    {
        cs++;
        // increasing the current size of the stack
        l.push_front(d);
    }
  
    // popping an element from the stack
    void pop()
    {
        if (cs <= 0) {
            // cannot pop us stack does not contain an
            // elements
            cout << "Stack empty" << endl;
        }
        else {
            // decreasing the current size of the stack
            cs--;
            l.pop_front();
        }
    }
  
    // if current size is 0 then stack is empty
    bool empty() { return cs == 0; }
  
    // getting the element present at the top of the stack
    T top() { return l.front(); }
    int size()
    {
        // getting the size of the stack
        return cs;
    }
  
    // printing the elements of the stack
    void print()
    {
        for (auto x: l) {
            cout << x << endl;
        }
    }
};
int main()
{
    Stack s;
    s.push(10); // pushing into the stack
    s.push(20);
    s.push(30);
    s.push(40);
    cout << "Current size of the stack is " << s.size()
         << endl;
    cout << "The top element of the stack is " << s.top()
         << endl;
    s.pop(); // popping from the stack
    cout << "The top element after 1 pop operation is "
         << s.top()
         << endl; // printing the top of the stack
    s.pop(); // popping
    cout << "The top element after 2 pop operations is "
         << s.top() << endl;
    cout << "Size of the stack after 2 pop operations is "
         << s.size() << endl;
    return 0;
}


输出
Current size of the stack is 4
The top element of the stack is 40
The top element after 1 pop operation is 30
The top element after 2 pop operations is 20
Size of the stack after 2 pop operations is 2

时间复杂度:对于堆栈中的入栈和出栈操作来说都是 O(1)。
辅助空间: O(N)

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