Python| Sympy Plane.are_concurrent() 方法

在 Simpy 中，函数Plane.are_concurrent()用于检查给定的平面序列是否并发。如果两个或多个平面的交点是一条公共线，则它们是并发的。

Syntax: Plane.are_concurrent()

Parameters:
 planes: sequence of planes

Returns:
 True: if they are concurrent, else False

示例 #1：

# import sympy, Point3D and Plane
from sympy import Point3D, Plane
  
# using Plane() 
p1 = Plane(Point3D(5, 0, 0), normal_vector =(1, -1, 1))
p2 = Plane(Point3D(0, -2, 0), normal_vector =(3, 1, 1))
  
# using are_concurrent()
areConcurrent = Plane.are_concurrent(p1, p2)
  
print(areConcurrent)

输出：

True

示例 #2：

# import sympy, Point3D and Plane
from sympy import Point3D, Plane
  
# using Plane() 
p1 = Plane(Point3D(5, 0, 0), normal_vector =(1, -1, 1))
p2 = Plane(Point3D(0, -2, 0), normal_vector =(3, 1, 1))
p3 = Plane(Point3D(0, -1, 0), normal_vector =(5, -1, 9))
  
# using are_concurrent()
areConcurrent = Plane.are_concurrent(p1, p2, p3)
  
print(areConcurrent)

输出：

False