在二叉树中创建偶数和奇数的循环
给定一棵二叉树,其节点结构包含数据部分、左右指针和任意指针 (abtr)。节点的值可以是任何正整数。问题是在二叉树中创建奇数和偶数循环。奇数循环是连接所有奇数节点的循环,同样偶数循环用于偶数节点。为了创建这样的循环,使用了每个节点的 abtr 指针。奇数节点(具有奇数的节点)的 abtr 指针指向树中的某个其他奇数节点。必须以这样一种方式创建循环,即我们可以从任何节点遍历该节点所属的循环中的所有节点。
例子:
Consider the binary tree given below
1
/ \
2 3
/ \ / \
4 5 6 7
Now with the help of abtr pointers of node,
we connect odd and even nodes as:
Odd loop
1 -> 5 -> 3 -> 7 -> 1(again pointing to first node
in the loop)
Even loop
2 -> 4 -> 6 -> 2(again pointing to first node
in the loop)
Nodes in the respective loop can be arranged in
any order. But from any node in the loop we should
be able to traverse all the nodes in the loop.
方法:以下步骤是:
- 将偶数和奇数节点的指针分别添加到even_ptrs和odd_ptrs数组。通过任何树的遍历,我们可以得到各自的节点指针。
- 对于even_ptrs和odd_ptrs数组,执行:
- 由于数组包含节点指针,因此考虑第 i 个索引处的元素,让它为node ,分配的 node->abtr = 第 (i+1) 个索引处的元素。
- 对于数组的最后一个元素,node->abtr = 索引 0 处的元素。
CPP
// C++ implementation to create odd and even loops
// in a binary tree
#include
using namespace std;
// structure of a node
struct Node
{
int data;
Node *left, *right, *abtr;
};
// Utility function to create a new node
struct Node* newNode(int data)
{
struct Node* node = new Node;
node->data = data;
node->left = node->right = node->abtr = NULL;
return node;
}
// preorder traversal to place the node pointer
// in the respective even_ptrs or odd_ptrs list
void preorderTraversal(Node *root, vector *even_ptrs,
vector *odd_ptrs)
{
if (!root)
return;
// place node ptr in even_ptrs list if
// node contains even number
if (root->data % 2 == 0)
(*even_ptrs).push_back(root);
// else place node ptr in odd_ptrs list
else
(*odd_ptrs).push_back(root);
preorderTraversal(root->left, even_ptrs, odd_ptrs);
preorderTraversal(root->right, even_ptrs, odd_ptrs);
}
// function to create the even and odd loops
void createLoops(Node *root)
{
vector even_ptrs, odd_ptrs;
preorderTraversal(root, &even_ptrs, &odd_ptrs);
int i;
// forming even loop
for (i=1; iabtr = even_ptrs[i];
// for the last element
even_ptrs[i-1]->abtr = even_ptrs[0];
// Similarly forming odd loop
for (i=1; iabtr = odd_ptrs[i];
odd_ptrs[i-1]->abtr = odd_ptrs[0];
}
// traversing the loop from any random
// node in the loop
void traverseLoop(Node *start)
{
Node *curr = start;
do
{
cout << curr->data << " ";
curr = curr->abtr;
} while (curr != start);
}
// Driver program to test above
int main()
{
// Binary tree formation
struct Node* root = NULL;
root = newNode(1); /* 1 */
root->left = newNode(2); /* / \ */
root->right = newNode(3); /* 2 3 */
root->left->left = newNode(4); /* / \ / \ */
root->left->right = newNode(5); /* 4 5 6 7 */
root->right->left = newNode(6);
root->right->right = newNode(7);
createLoops(root);
// traversing odd loop from any
// random odd node
cout << "Odd nodes: ";
traverseLoop(root->right);
cout << endl << "Even nodes: ";
// traversing even loop from any
// random even node
traverseLoop(root->left);
return 0;
}
Java
// Java implementation to create odd and even loops
// in a binary tree
import java.util.*;
class GFG
{
// structure of a node
static class Node
{
int data;
Node left, right, abtr;
};
// Utility function to create a new node
static Node newNode(int data)
{
Node node = new Node();
node.data = data;
node.left = node.right = node.abtr = null;
return node;
}
static Vector even_ptrs = new Vector<>();
static Vector odd_ptrs = new Vector<>();
// preorder traversal to place the node pointer
// in the respective even_ptrs or odd_ptrs list
static void preorderTraversal(Node root)
{
if (root == null)
return;
// place node ptr in even_ptrs list if
// node contains even number
if (root.data % 2 == 0)
(even_ptrs).add(root);
// else place node ptr in odd_ptrs list
else
(odd_ptrs).add(root);
preorderTraversal(root.left);
preorderTraversal(root.right);
}
// function to create the even and odd loops
static void createLoops(Node root)
{
preorderTraversal(root);
int i;
// forming even loop
for (i = 1; i < even_ptrs.size(); i++)
even_ptrs.get(i - 1).abtr = even_ptrs.get(i);
// for the last element
even_ptrs.get(i - 1).abtr = even_ptrs.get(0);
// Similarly forming odd loop
for (i = 1; i < odd_ptrs.size(); i++)
odd_ptrs.get(i - 1).abtr = odd_ptrs.get(i);
odd_ptrs.get(i - 1).abtr = odd_ptrs.get(0);
}
// traversing the loop from any random
// node in the loop
static void traverseLoop(Node start)
{
Node curr = start;
do
{
System.out.print(curr.data + " ");
curr = curr.abtr;
} while (curr != start);
}
// Driver code
public static void main(String[] args)
{
// Binary tree formation
Node root = null;
root = newNode(1); /* 1 */
root.left = newNode(2); /* / \ */
root.right = newNode(3); /* 2 3 */
root.left.left = newNode(4); /* / \ / \ */
root.left.right = newNode(5); /* 4 5 6 7 */
root.right.left = newNode(6);
root.right.right = newNode(7);
createLoops(root);
// traversing odd loop from any
// random odd node
System.out.print("Odd nodes: ");
traverseLoop(root.right);
System.out.print( "\nEven nodes: ");
// traversing even loop from any
// random even node
traverseLoop(root.left);
}
}
// This code is contributed by aashish1995
Python3
# Python3 implementation to create odd and even loops
# in a binary tree
# structure of a node
class Node:
def __init__(self, x):
self.data = x
self.left = None
self.right = None
self.abtr = None
even_ptrs = []
odd_ptrs = []
# preorder traversal to place the node pointer
# in the respective even_ptrs or odd_ptrs list
def preorderTraversal(root):
global even_ptrs, odd_ptrs
if (not root):
return
# place node ptr in even_ptrs list if
# node contains even number
if (root.data % 2 == 0):
even_ptrs.append(root)
# else place node ptr in odd_ptrs list
else:
odd_ptrs.append(root)
preorderTraversal(root.left)
preorderTraversal(root.right)
# function to create the even and odd loops
def createLoops(root):
preorderTraversal(root)
# forming even loop
i = 1
while i < len(even_ptrs):
even_ptrs[i - 1].abtr = even_ptrs[i]
i += 1
# for the last element
even_ptrs[i - 1].abtr = even_ptrs[0]
# Similarly forming odd loop
i = 1
while i < len(odd_ptrs):
odd_ptrs[i - 1].abtr = odd_ptrs[i]
i += 1
odd_ptrs[i - 1].abtr = odd_ptrs[0]
#traversing the loop from any random
#node in the loop
def traverseLoop(start):
curr = start
while True and curr:
print(curr.data, end = " ")
curr = curr.abtr
if curr == start:
break
print()
# Driver program to test above
if __name__ == '__main__':
# Binary tree formation
root = None
root = Node(1) #/* 1 */
root.left = Node(2) # /* / \ */
root.right = Node(3) #/* 2 3 */
root.left.left = Node(4) #/* / \ / \ */
root.left.right = Node(5) #/* 4 5 6 7 */
root.right.left = Node(6)
root.right.right = Node(7)
createLoops(root)
# traversing odd loop from any
# random odd node
print("Odd nodes:", end = " ")
traverseLoop(root.right)
print("Even nodes:", end = " ")
# traversing even loop from any
# random even node
traverseLoop(root.left)
# This code is contributed by mohit kumar 29
C#
// C# implementation to create odd and even loops
// in a binary tree
using System;
using System.Collections.Generic;
class GFG
{
// structure of a node
public
class Node
{
public
int data;
public
Node left, right, abtr;
};
// Utility function to create a new node
static Node newNode(int data)
{
Node node = new Node();
node.data = data;
node.left = node.right = node.abtr = null;
return node;
}
static List even_ptrs = new List();
static List odd_ptrs = new List();
// preorder traversal to place the node pointer
// in the respective even_ptrs or odd_ptrs list
static void preorderTraversal(Node root)
{
if (root == null)
return;
// place node ptr in even_ptrs list if
// node contains even number
if (root.data % 2 == 0)
(even_ptrs).Add(root);
// else place node ptr in odd_ptrs list
else
(odd_ptrs).Add(root);
preorderTraversal(root.left);
preorderTraversal(root.right);
}
// function to create the even and odd loops
static void createLoops(Node root)
{
preorderTraversal(root);
int i;
// forming even loop
for (i = 1; i < even_ptrs.Count; i++)
even_ptrs[i - 1].abtr = even_ptrs[i];
// for the last element
even_ptrs[i - 1].abtr = even_ptrs[0];
// Similarly forming odd loop
for (i = 1; i < odd_ptrs.Count; i++)
odd_ptrs[i - 1].abtr = odd_ptrs[i];
odd_ptrs[i - 1].abtr = odd_ptrs[0];
}
// traversing the loop from any random
// node in the loop
static void traverseLoop(Node start)
{
Node curr = start;
do
{
Console.Write(curr.data + " ");
curr = curr.abtr;
} while (curr != start);
}
// Driver code
public static void Main(String[] args)
{
// Binary tree formation
Node root = null;
root = newNode(1); /* 1 */
root.left = newNode(2); /* / \ */
root.right = newNode(3); /* 2 3 */
root.left.left = newNode(4); /* / \ / \ */
root.left.right = newNode(5); /* 4 5 6 7 */
root.right.left = newNode(6);
root.right.right = newNode(7);
createLoops(root);
// traversing odd loop from any
// random odd node
Console.Write("Odd nodes: ");
traverseLoop(root.right);
Console.Write( "\nEven nodes: ");
// traversing even loop from any
// random even node
traverseLoop(root.left);
}
}
// This code is contributed by gauravrajput1
Javascript
输出:
Odd nodes: 3 7 1 5
Even nodes: 2 4 6