C++中的restder()

该函数还用于返回其参数中提到的2个浮点数的余数(模)。

余数=数字– rquot *十进制

其中，rquot是以下值的结果：numer / denom，四舍五入到最接近的整数值(中间的情况下四舍五入到偶数)。

句法 ：

double remainder(double a, double b)
float remainder(float a, float b)
long double remainder(long double a, long double b)
Parameter:
a and b are the values 
of numerator and denominator.


Return:
The remainder() function returns the floating 
point remainder of numerator/denominator 
rounded to nearest.

错误或异常：必须同时提供两个参数，否则将产生错误–此类调用’remainder()’的函数不匹配。

＃代码1

// CPP program to demonstrate 
// remainder() function
#include 
#include 
  
using namespace std;
  
int main()
{
    double a, b;
    double answer;
  
    a = 50.35;
    b = -4.1;
  
    // here quotient is -12.2805 and rounded to nearest value then
    // rquot = -12.
    // remainder = 50.35 – (-12 * -4.1)
    answer = remainder(a, b);
  
    cout << "Remainder of " << a << "/" << b << " is " << answer << endl;
  
    a = 16.80;
    b = 3.5;
  
    // here quotient is 4.8 and rounded to nearest value then
    // rquot = -5.
    // remainder = 16.80 – (5 * 3.5)
    answer = remainder(a, b);
  
    cout << "Remainder of " << a << "/" << b << " is " << answer << endl;
  
    a = 16.80;
    b = 0;
    answer = remainder(a, b);
    cout << "Remainder of " << a << "/" << b << " is " << answer << endl;
  
    return 0;
}

输出 ：

Remainder of 50.35/-4.1 is 1.15
Remainder of 16.8/3.5 is -0.7
Remainder of 16.8/0 is -nan

＃代码2

// CPP program to demonstrate 
// remainder() function
#include 
#include 
  
using namespace std;
  
int main()
{
    int a = 50;
    double b = 41.35, answer;
  
    answer = remainder(a, b);
    cout << "Remainder of " << a << "/" << b << " = " << answer << endl;
  
    return 0;
}

输出 ：

Remainder of 50/41.35 = 8.65

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