📜  C#中的Double.IsInfinity()方法

📅  最后修改于: 2021-05-29 14:35:25             🧑  作者: Mango

在C#中, Double.IsInfinity()是Double结构方法。此方法用于检查指定值的计算结果是正无穷大还是负无穷大。在执行一些数学运算时,有可能获得正无穷大或负无穷大的结果。例如:如果任何正值除以零,则结果为正无穷大。

返回类型:如果指定值的计算结果为正无穷大或负无穷大,则此函数返回布尔值True ,否则返回False

例子:

Input  : d = 10 / 0.0 
Output : True

Input  : d = 7.997e307 + 9.985e307
Output : True

笔记:

  • 如果任何浮点运算的结果超过Double.MaxValue(即1.79769313486232E + 308),则视为正无穷大;如果结果小于Double.MinValue(即-1.79769313486232E + 308),则视为负无穷大。
  • 浮点运算返回Infinity (正无穷大)或-Infinity (负无穷大)以指示溢出情况。

代码:演示Double.IsInfinity(Double)方法

// C# program to illustrate the
// Double.IsInfinity() Method
using System;
  
class GFG {
  
    // Main method
    static public void Main()
    {
  
        // Dividing a Positive number by zero
        // results in positive infinity.
  
        double zero = 0.0;
        double value = 10.0;
        double result = value / zero;
  
        // Printing result
        Console.WriteLine(result);
  
        // Check result using IsInfinity() Method
        Console.WriteLine(Double.IsInfinity(result));
  
        // Result of any operation that
        // exceeds Double.MaxValue 
        // (i.e 1.79769313486232E+308)
        // is Positive infintity
        result = Double.MaxValue + 9.985e307;
  
        // Printing result
        Console.WriteLine(result);
  
        // Check result using IsInfinity() Method
        Console.WriteLine(Double.IsInfinity(result));
  
        // Result of any operation that
        // is less than Double.MinValue 
        // (i.e -1.79769313486232E+308)
        // is Negative infintity
        result = Double.MinValue - 9.985e307;
  
        // Printing result
        Console.WriteLine(result);
  
        // Check result using IsInfinity() Method
        Console.WriteLine(Double.IsInfinity(result));
    }
}
输出:
Infinity
True
Infinity
True
-Infinity
True