Java中的 CompositeName endsWith() 方法及示例

javax.naming.CompositeName 类的endsWith()方法用于检查作为参数传递的复合名称是否是该复合名称的后缀。如果该复合名称对象以“X”结尾，则复合名称“X”是该复合名称的后缀。如果 X 为 null 或不是复合名称对象，则返回 false。

句法：

public boolean endsWith(Name n)

参数：此方法接受n ，它是要检查的可能为空的复合名称。

返回值：如果 n 是 CompositeName 并且是该复合名称的后缀，则此方法返回 true，否则返回 false。

下面的程序说明了 CompositeName.endsWith() 方法：
方案一：

// Java program to demonstrate
// CompositeName.endsWith()
  
import java.util.Properties;
import javax.naming.CompositeName;
import javax.naming.InvalidNameException;
  
public class GFG {
    public static void main(String[] args)
        throws InvalidNameException
    {
  
        // create composite name object
        CompositeName CompositeName1
            = new CompositeName("1/2/3/4/5/6");
        CompositeName CompositeName2
            = new CompositeName("5/6");
  
        // apply endsWith()
        boolean endWithFlag
            = CompositeName1.endsWith(CompositeName2);
  
        // print value
        if (endWithFlag)
            System.out.println("CompositeName1 ends with "
                               + " CompositeName2");
        else
            System.out.println("CompositeName1 not ends with "
                               + " CompositeName2");
    }
}

输出：

CompositeName1 ends with  CompositeName2

方案二：

// Java program to demonstrate
// CompositeName.endsWith() method
  
import java.util.Properties;
import javax.naming.CompositeName;
import javax.naming.InvalidNameException;
  
public class GFG {
    public static void main(String[] args)
        throws InvalidNameException
    {
  
        // create composite name object
        CompositeName CompositeName1
            = new CompositeName("c/e/d/v/a/b/z/y/x/f");
        CompositeName CompositeName2
            = new CompositeName("z/y/x");
  
        // apply endsWith()
        boolean endWithFlag
            = CompositeName1.endsWith(CompositeName2);
  
        // print value
        if (endWithFlag)
            System.out.println("CompositeName1 ends with "
                               + " CompositeName2");
        else
            System.out.println("CompositeName1 not ends with "
                               + " CompositeName2");
    }
}

输出：

CompositeName1 not ends with  CompositeName2

参考资料：https://docs.oracle.com/javase/10/docs/api/javax/naming/CompositeName.html#endsWith(javax.naming.Name)