C程序，用于在结构中动态存储数据

该程序要求用户存储noOfRecords的值，并使用malloc() 函数动态地为noOfRecords结构变量分配内存。

演示结构的动态内存分配

#include 
#include 
struct course {
    int marks;
    char subject[30];
};

int main() {
    struct course *ptr;
    int i, noOfRecords;
    printf("Enter the number of records: ");
    scanf("%d", &noOfRecords);

    // Memory allocation for noOfRecords structures
    ptr = (struct course *)malloc(noOfRecords * sizeof(struct course));
    for (i = 0; i < noOfRecords; ++i) {
        printf("Enter the name of the subject and marks respectively:\n");
        scanf("%s %d", (ptr + i)->subject, &(ptr + i)->marks);
    }

    printf("Displaying Information:\n");
    for (i = 0; i < noOfRecords; ++i)
        printf("%s\t%d\n", (ptr + i)->subject, (ptr + i)->marks);

    return 0;
}

输出

Enter the number of records: 2
Enter the name of the subject and marks respectively:
Programming
22
Enter the name of the subject and marks respectively:
Structure
33

Displaying Information:
Programming      22
Structure        33

在此示例中，您将学习存储用户使用动态内存分配输入的信息。

演示结构的动态内存分配