📜  C程序通过将结构传递给函数来添加两个复数

📅  最后修改于: 2020-10-04 11:20:41             🧑  作者: Mango

在此示例中,您将学习将两个复数作为结构并通过创建用户定义的函数将它们相加。

加两个复数
#include 
typedef struct complex {
    float real;
    float imag;
} complex;

complex add(complex n1, complex n2);

int main() {
    complex n1, n2, result;

    printf("For 1st complex number \n");
    printf("Enter the real and imaginary parts: ");
    scanf("%f %f", &n1.real, &n1.imag);
    printf("\nFor 2nd complex number \n");
    printf("Enter the real and imaginary parts: ");
    scanf("%f %f", &n2.real, &n2.imag);

    result = add(n1, n2);

    printf("Sum = %.1f + %.1fi", result.real, result.imag);
    return 0;
}

complex add(complex n1, complex n2) {
    complex temp;
    temp.real = n1.real + n2.real;
    temp.imag = n1.imag + n2.imag;
    return (temp);
}

输出

For 1st complex number
Enter the real and imaginary parts: 2.1
-2.3

For 2nd complex number
Enter the real and imaginary parts: 5.6
23.2
Sum = 7.7 + 20.9i

在此程序中,声明了一个名为complex的结构。它有两个成员: realimag 。然后,我们从该结构创建了两个变量n1n2

这两个结构变量传递给add() 函数。该函数计算总和并返回包含该总和的结构。

最后,从main() 函数复数和。