单链表所有素节点的和与积

给定一个包含 N 个节点的单链表，任务是从列表中找出所有素数节点的总和和乘积。
例子：

Input : List = 15 -> 16 -> 6 -> 7 -> 17
Output : Product = 119, Sum = 24
Prime nodes are 7, 17.

Input : List = 15 -> 3 -> 4 -> 2 -> 9
Output : Product = 6, Sum = 5

方法：思路是逐个遍历单链表的节点，检查当前节点是否为素数。求素数节点的数据的总和和乘积。
下面是上述想法的实现：

C++

// C++ implementation to find sum and
// product of all of prime nodes of
// the singly linked list
 
#include 
 
using namespace std;
 
// Node of the singly linked list
struct Node {
    int data;
    Node* next;
};
 
// Function to insert a node at the beginning
// of the singly Linked List
void push(Node** head_ref, int new_data)
{
    // allocate node
    Node* new_node = (Node*)malloc(sizeof(struct Node));
 
    // put in the data
    new_node->data = new_data;
 
    // link the old list off the new node
    new_node->next = (*head_ref);
 
    // move the head to point to the new node
    (*head_ref) = new_node;
}
 
// Function to check if a number is prime
bool isPrime(int n)
{
    // Corner cases
    if (n <= 1)
        return false;
    if (n <= 3)
        return true;
 
    // This is checked so that we can skip
    // middle five numbers in below loop
    if (n % 2 == 0 || n % 3 == 0)
        return false;
 
    for (int i = 5; i * i <= n; i = i + 6)
        if (n % i == 0 || n % (i + 2) == 0)
            return false;
 
    return true;
}
 
// Function to find sum and product of all
// prime nodes of the singly linked list
void sumAndProduct(Node* head_ref)
{
    int prod = 1;
    int sum = 0;
 
    Node* ptr = head_ref;
 
    // Traverse the linked list
    while (ptr != NULL) {
        // if current node is prime,
        // Find sum and product
        if (isPrime(ptr->data)) {
            prod *= ptr->data;
            sum += ptr->data;
        }
 
        ptr = ptr->next;
    }
 
    cout << "Sum = " << sum << endl;
    cout << "Product = " << prod;
}
 
// Driver program
int main()
{
    // start with the empty list
    Node* head = NULL;
 
    // create the linked list
    // 15 -> 16 -> 7 -> 6 -> 17
    push(&head, 17);
    push(&head, 7);
    push(&head, 6);
    push(&head, 16);
    push(&head, 15);
 
    sumAndProduct(head);
 
    return 0;
}

Java

// Java implementation to find sum and
// product of all of prime nodes of
// the singly linked list
class GFG
{
 
// Node of the singly linked list
static class Node
{
    int data;
    Node next;
};
 
// Function to insert a node at the beginning
// of the singly Linked List
static Node push(Node head_ref, int new_data)
{
    // allocate node
    Node new_node =new Node();
 
    // put in the data
    new_node.data = new_data;
 
    // link the old list off the new node
    new_node.next = (head_ref);
 
    // move the head to point to the new node
    (head_ref) = new_node;
    return head_ref;
}
 
// Function to check if a number is prime
static boolean isPrime(int n)
{
    // Corner cases
    if (n <= 1)
        return false;
    if (n <= 3)
        return true;
 
    // This is checked so that we can skip
    // middle five numbers in below loop
    if (n % 2 == 0 || n % 3 == 0)
        return false;
 
    for (int i = 5; i * i <= n; i = i + 6)
        if (n % i == 0 || n % (i + 2) == 0)
            return false;
 
    return true;
}
 
// Function to find sum and product of all
// prime nodes of the singly linked list
static void sumAndProduct(Node head_ref)
{
    int prod = 1;
    int sum = 0;
 
    Node ptr = head_ref;
 
    // Traverse the linked list
    while (ptr != null)
    {
        // if current node is prime,
        // Find sum and product
        if (isPrime(ptr.data))
        {
            prod *= ptr.data;
            sum += ptr.data;
        }
 
        ptr = ptr.next;
    }
 
    System.out.println("Sum = " + sum );
    System.out.println( "Product = " + prod);
}
 
// Driver code
public static void main(String args[])
{
    // start with the empty list
    Node head = null;
 
    // create the linked list
    // 15 . 16 . 7 . 6 . 17
    head=push(head, 17);
    head=push(head, 7);
    head=push(head, 6);
    head=push(head, 16);
    head=push(head, 15);
 
    sumAndProduct(head);
 
}
}
 
// This code is contributed by Arnab Kundu

Python

# Python implementation to find sum and
# product of all of prime nodes of
# the singly linked list
 
# Link list node
class Node:
     
    def __init__(self, data):
        self.data = data
        self.next = next
         
# Function to insert a node at the beginning
# of the singly Linked List
def push( head_ref, new_data) :
 
    # allocate node
    new_node =Node(0)
 
    # put in the data
    new_node.data = new_data
 
    # link the old list off the new node
    new_node.next = (head_ref)
 
    # move the head to point to the new node
    (head_ref) = new_node
    return head_ref
 
# Function to check if a number is prime
def isPrime(n) :
 
    # Corner cases
    if (n <= 1) :
        return False
    if (n <= 3) :
        return True
 
    # This is checked so that we can skip
    # middle five numbers in below loop
    if (n % 2 == 0 or n % 3 == 0) :
        return False
 
    i = 5
    while ( i * i <= n) :
        if (n % i == 0 or n % (i + 2) == 0) :
            return False
        i = i + 6
    return True
 
# Function to find sum and product of all
# prime nodes of the singly linked list
def sumAndProduct(head_ref) :
 
    prod = 1
    sum = 0
 
    ptr = head_ref
 
    # Traverse the linked list
    while (ptr != None):
     
        # if current node is prime,
        # Find sum and product
        if (isPrime(ptr.data)):
         
            prod *= ptr.data
            sum += ptr.data
         
        ptr = ptr.next
     
    print("Sum = " , sum )
    print( "Product = " , prod)
 
# Driver code
 
# start with the empty list
head = None
 
# create the linked list
# 15 . 16 . 7 . 6 . 17
head = push(head, 17)
head = push(head, 7)
head = push(head, 6)
head = push(head, 16)
head = push(head, 15)
 
sumAndProduct(head)
 
 
# This code is contributed by Arnab Kundu

C#

// C# implementation to find sum and
// product of all of prime nodes of
// the singly linked list
using System;
     
class GFG
{
 
// Node of the singly linked list
public class Node
{
    public int data;
    public Node next;
};
 
// Function to insert a node at the beginning
// of the singly Linked List
static Node push(Node head_ref, int new_data)
{
    // allocate node
    Node new_node =new Node();
 
    // put in the data
    new_node.data = new_data;
 
    // link the old list off the new node
    new_node.next = (head_ref);
 
    // move the head to point to the new node
    (head_ref) = new_node;
    return head_ref;
}
 
// Function to check if a number is prime
static bool isPrime(int n)
{
    // Corner cases
    if (n <= 1)
        return false;
    if (n <= 3)
        return true;
 
    // This is checked so that we can skip
    // middle five numbers in below loop
    if (n % 2 == 0 || n % 3 == 0)
        return false;
 
    for (int i = 5; i * i <= n; i = i + 6)
        if (n % i == 0 || n % (i + 2) == 0)
            return false;
 
    return true;
}
 
// Function to find sum and product of all
// prime nodes of the singly linked list
static void sumAndProduct(Node head_ref)
{
    int prod = 1;
    int sum = 0;
 
    Node ptr = head_ref;
 
    // Traverse the linked list
    while (ptr != null)
    {
        // if current node is prime,
        // Find sum and product
        if (isPrime(ptr.data))
        {
            prod *= ptr.data;
            sum += ptr.data;
        }
 
        ptr = ptr.next;
    }
 
    Console.WriteLine("Sum = " + sum);
    Console.WriteLine( "Product = " + prod);
}
 
// Driver code
public static void Main(String []args)
{
    // start with the empty list
    Node head = null;
 
    // create the linked list
    // 15 . 16 . 7 . 6 . 17
    head = push(head, 17);
    head = push(head, 7);
    head = push(head, 6);
    head = push(head, 16);
    head = push(head, 15);
 
    sumAndProduct(head);
}
}
 
// This code is contributed by 29AjayKumar

Javascript

// javascript implementation to find sum and
// product of all of prime nodes of
// the singly linked list     // Node of the singly linked list
class Node {
    constructor() {
        this.data = 0;
        this.next = null;
    }
}
 
    // Function to insert a node at the beginning
    // of the singly Linked List
    function push(head_ref , new_data) {
        // allocate node
var new_node = new Node();
 
        // put in the data
        new_node.data = new_data;
 
        // link the old list off the new node
        new_node.next = (head_ref);
 
        // move the head to point to the new node
        (head_ref) = new_node;
        return head_ref;
    }
 
    // Function to check if a number is prime
    function isPrime(n) {
        // Corner cases
        if (n <= 1)
            return false;
        if (n <= 3)
            return true;
 
        // This is checked so that we can skip
        // middle five numbers in below loop
        if (n % 2 == 0 || n % 3 == 0)
            return false;
 
        for (i = 5; i * i <= n; i = i + 6)
            if (n % i == 0 || n % (i + 2) == 0)
                return false;
 
        return true;
    }
 
    // Function to find sum and product of all
    // prime nodes of the singly linked list
    function sumAndProduct(head_ref) {
        var prod = 1;
        var sum = 0;
 
var ptr = head_ref;
 
        // Traverse the linked list
        while (ptr != null) {
            // if current node is prime,
            // Find sum and product
            if (isPrime(ptr.data)) {
                prod *= ptr.data;
                sum += ptr.data;
            }
 
            ptr = ptr.next;
        }
 
        document.write("Sum = " + sum);
        document.write("<br/>Product = " + prod);
    }
 
    // Driver code
     
        // start with the empty list
var head = null;
 
        // create the linked list
        // 15 . 16 . 7 . 6 . 17
        head = push(head, 17);
        head = push(head, 7);
        head = push(head, 6);
        head = push(head, 16);
        head = push(head, 15);
 
        sumAndProduct(head);
 
 
// This code contributed by umadevi9616

输出：

Sum = 24
Product = 119

时间复杂度： O(N)，其中 N 是链表中的节点数。